UTC-IC L3380L-XX-AF5-R

UNISONIC TECHNOLOGIES CO., LTD
L3380
CMOS IC
PWM STEP UP DC-DC
CONTROLLER
DESCRIPTION
The L3380 is PWM step up DC-DC switching controller that
operates from 0.9V. The low start up input voltage makes L3380
specially designed for powering portable equipment from one or two
cells battery packs. This device consist of a soft start circuit, a
reference voltage source, an error amplifier, an oscillator, a phase
compensation, a PWM controller and an output drive circuit for
driving external power transistor.
Additionally, a chip enable feature is provided to power down the
converter for extended battery life. The device features a voltage
mode PWM control loop, providing stable and high efficiency
operation over a broad load current range.
3
2
1
5
4
SOT-25
*Pb-free plating product number: L3380L
FEATURES
* 0.9V low start-up Input voltage at 1mA load
* Low operation current
* 0.5uA low shutdown current
* Fix frequency PWM at 100KHZ
* Built in PWM switching control circuit ,duty ratio is 0~83%
* Output voltage:0.1V step setting is available between 2.0V and
6.5V
* Soft start time: 6ms
* Shutdown function
APPLICATIONS
*Portable devices
*Electronic games
*Portable audio (MP3)
*Personal digital assistant (PDA)
*Digital still cameras(DSC)
*Camcorders
*White LED driver
*Single and dual-cell battery operated products
ORDERING INFORMATION
Order Number
Normal
Lead Free Plating
L3380-xx-AF5-R
L3380L-xx-AF5-R
Package
Packing
SOT-25
Tape Reel
L3380L-xx-AF5-R
(1)Packing Type
(2)Package Type
(1) R: Tape Reel
(2) AF5: SOT-25
(3)Output Voltage Code
(3) xx: refer to Marking Information
(4)Lead Plating
(4) L: Lead Free Plating, Blank: Pb/Sn
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QW-R502-099,A
L3380
CMOS IC
MARKING INFORMATION
PACKAGE
VOLTAGE CODE
SOT-25
18:1.8V
21:2.1V
25:2.5V
27:2.7V
30:3.0V
33:3.3V
40:4.0V
50:5.0V
MARKING
3
2
1
H0
Voltage Code
Lead Plating
4
5
PIN DESCRIPTION
PIN
NAME
1
SHUTDOWN
2
3
4
5
VOUT
NC
VSS
EXT
FUNCTION
Shutdown control input, “H” : normal operation
“L” : stop step up( whole circuit stop).
Power supply and voltage output.
No connection.
Ground.
Switching the circuit by connecting to a transistor.
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L3380
CMOS IC
BLOCK DIAGRAM
VOUT
2
L3380
Error Amp
PWM
COMP
Driver
5
EXT
Phase
compensation
Voltage
Reference
Oscillator
Soft Start
4
1
VSS
SHUTDOWN
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CMOS IC
ABSOLUTE MAXIMUM RATINGS
PARAMETER
SYMBOL
RATINGS
UNIT
VOUT Pin Voltage
VOUT
12
V
SHUTDOWN Pin Voltage
VSHUTDOWN
VSS-0.3~12
V
EXT Pin Voltage
VEXT
-0.3~ VOUT+0.3
V
EXT Pin Current
IEXT
±80
mA
Power Dissipation
PD
250
mW
Operating Ambient Temperature
TOPR
-40~+85
℃
Storage Temperature
TSTG
-40~ +125
℃
Note: Absolute maximum ratings are those values beyond which the device could be permanently damaged.
Absolute maximum ratings are stress ratings only and functional device operation is not implied.
ELECTRICAL CHARACTERISTICS
Refer to the test circuit, TOPR=25ºC, VIN=VOUT (S)*0.6, IOUT=VOUT (S)/50Ω, unless otherwise specified.
SYMBOL
TEST
CIRCUIT
VOUT
2
IS1
IS2
VIN
1
1
2
VHOLD
2
Measured by decreasing VIN
voltage gradually, when
IOUT=1mA.
Operation Start Voltage
VST1
2
IOUT=1mA
Oscillation Start Voltage
VST2
1
fOSC
Duty
⊿LNR
⊿LDR
1
1
2
2
Temperature Coefficient
ET
2
Efficiency
Soft Start time
SHUTDOWN
Shutdown Supply Current
Shutdown Pin Input
Current
EF
Ts
2
2
ISS
ISH
ISL
1
PARAMETER
TEST CONDITION
MIN
TYP
MAX
UNIT
TOTAL DEVICE
Output Voltage
Supply Current 1
Supply Current 2
Input Voltage
Operation Holding Voltage
Oscillation Frequency
Duty Ratio
Line Regulation
Load Regulation
1
VIH
Shutdown Pin Input
Voltage Threshold
VIL1
1
V IL2
VOUT
(S)*0.976
VOUT=VOUT (S)*0.95
VOUT=VIN (S)+0.5V
Increase the VIN until EXT pin
output the oscillating signal
VOUT=VOUT (S)*0.95
VOUT=VOUT (S)*0.95
VIN=VOUT (S)*0.4 to *0.6
IOUT=10uA to VOUT (S)/50*1.25
⊿VOUT/(⊿TOPR*VOUT)
TOPR=-40℃ to +85℃
39.8
6.3
VOUT
(S)*1.024
66.4
12.5
10
0.7
85
75
V
uA
uA
V
V
100
83
30
30
0.9
V
0.8
V
115
90
60
60
12.0
KHZ
%
mV
mV
ppm/
℃
%
ms
0.5
0.1
-0.1
uA
uA
uA
±50
3.0
VSHUTDOWN=0
VSHUTDOWN=VOUT (S)*0.95
VSHUTDOWN=0
Shutdown pin “L” to “H” until
EXT output oscillating signal
Shutdown pin
VOUT≥1.5V
“H” to “L” until
EXT output
oscillating signal VOUT<1.5V
VOUT (S)
86
6.0
0.75
V
0.3
V
0.2
V
EXT
EXT Pin Current
IEXTH
IEXTL
1
1
VEXT=VOUT (S) -0.4V
VEXT= 0.4V
-16.1
27.4
-32.3
54.8
mA
mA
Note: VOUT (S) is the value of the set output voltage.
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L3380
CMOS IC
APPLICATION CIRCUIT
L1
D1
M1FH3
CDRH8D28-470
VOUT
C2
VIN
C1
Q1
FDN335N
C3
F93
L3380
EXT
OUT
SHUTDOWN
R1
VSS
TEST CIRCUIT
1.
EXT
Oscilloscope
VOUT
SHUTDOWN
+
-
VIN
+
VSS
0.1u
+
-
47u
2.
VIN
+
+
-
-
47u
+
EXT
VOUT
0.1u
47u
-
v
SHUTDOWN
VSS
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L3380
CMOS IC
APPLICATION CIRCUIT INFORMATION
The following equations show the relation of the basic design parameters.
1. Refer to the application circuit, the increasing inductor current when the switch is turn on is given by the following
equation
∆iL + =
1
1
d
U LTON = (U IN − U S )
L
L
f
( U IN :input voltage ;
U S :transistor saturation voltage)
The decreasing inductor current when the switch is turn off can derive by the equation below
1
1
1− d
U LTOFF = − (U O + U D − U IN )
( U D :diode forward voltage)
L
L
f
+
−
according to ∆iL + ∆iL = 0 ,the duty ratio is given by
U + U D − U IN
d= O
UO + U D − U S
IO
2. The average current flowing through the inductor is I L =
1− d
3. We note that I O = (1 − d ) I L
I
then we can write: I O = (1 − d ) L • ∆iL
∆iL
1
substituting ∆iL = U LTOFF ∆iL for equation above, output current is given by
L
∆i
1
1
I O = (1 − d ) •
• U LTOFF ( ICR = L )
IL
ICR L
1
1
1− d
I O = (1 − d ) •
• (Uo + U D − U IN )
ICR L
f
∆iL − =
IO =(1-d ) 2•
UO+UD – UIN
ICR • L• f
derive that
L=
(1– d) 2(UO+UD-UIN)
ICR • IO • f
4. The peak current of the inductor is given by
1
I PK = I L + ∆iL
2
1 ∆iL
I PK = I L +
• IL
2 IL
∆i
according to ICR = L
IL
1
I PK = I L + ICR • I L
2
derive that
Then derive the following equation for peak current of inductor
1
I PK = I L (1 + ICR)
2
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L3380
CMOS IC
APPLICATION CIRCUIT INFORMATION (Cont.)
5. Charge stores in C3 during charging up is given by
we can write
∆Q = ( I L − I O ) •
∆Q = I C • TOFF
1− d
f
6. Output ripple voltage is given by
VPP = ∆U C + ESR • ( I L − I O )
VPP =
(ESR: equivalent series resistance of the output capacitor)
∆Q
+ ESR • ( I L − I O )
C
Then we give the following example about choosing external components by considering the design parameters.
Design parameters:
Assume
d=
UD
and
U IN =1.5V Uo =2.1V I O =200mA VPP =100mV f=300KHZ ICR=0.2
US
are both 0.3V, the duty ratio is
U O + U D − U IN 2.1 + 0.3 − 1.5
=
= 0.429
U O + U D − U S 2.1 + 0.3 − 0.3
In order to generate the desired output current and ICR, the value of inductor should meets the following formula
L≤
(1– d) 2(UO+UD-UIN)
ICR • IO • f
=
(1– 0.429)2(2.1V+0.3V-1.5V)
= 24.5uH
0.2×0.2A×300000HZ
Calculate the average current and the peak current of inductor
IL =
IO
0.2 A
=
= 0.35 A
1 − d 1 − 0.429
I PK = I L (1 +
1
1
ICR) = 0.35 A × (1 + × 0.2) = 0.385 A
2
2
So, we make a trial of choosing a 22uH inductor that allowable maximum current is lager than 0.385A.
Determine the delta charge stores in C3 during charging up
∆Q = ( I L − I O ) •
1− d
1 − 0.429
= (0.35 A − 0.2 A) ×
= 0.286uC
f
300000 HZ
Assume the ESR of C3 is 0.15Ω, determine the value of C3
∆Q
0.286 × 10−6 C
C≥
=
= 3.69uF
VPP − ESR • ( I L − I O ) 0.1 − 0.15Ω × (0.35 A − 0.2 A)
Therefore, a Tantalum capacitor with value of 10uF and ESR of 0.15Ω can be used as output capacitor. However,
the optimized value should be obtained by experiment.
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L3380
CMOS IC
EXTERNAL COMPONENTS
1. Diode (D1)
The diode is the largest source of loss in DC-DC converters. The most important parameters which affect the
efficiency are the forward voltage drop
UD
and the reverse recovery time. The forward voltage drop creates a loss
just by having a voltage across the device while a current flowing through it. The reverse recovery time generates a
loss when the diode is reverse biased, and the current appears to actually flow backwards through the diode due to
the minority carriers being swept from the P-N junction. A Schottky diode with the following characteristics is
recommended:
*Low forward voltage:
U D < 0.3V
*Fast reverse recovery time/switching speed:
*Rated current:
≤ 50nS
> I PK
*Reverse voltage:
≥ UO + U D
2. Inductor (L1)
Low inductance values supply higher output current, but also increase the ripple and reduce efficiency. Choose a low
DC-resistance inductor to minimize loss. It is necessary to choose an inductor with saturation current greater than
the peak current that the inductor will encounter in the application. Saturation occurs when the inductor’s magnetic
flux density reaches the maximum level the core can support and inductance falls.
3. Capacitor (C1,C3)
The input capacitor C1 improves the efficiency by reducing the power impedance and stabilizing the input current.
Select a C1 value according to the impedance of the power supply used. Small Equivalent Series Resistance(ESR)
Tantalum or ceramic capacitor with an appropriate value should be suitable
The output capacitor is used for smoothing the output voltage and sustaining the output voltage when the switch is
on. Select an appropriate capacitor depending on the ripple voltage that increases in case of a higher output voltage
or a higher load current. The capacitor value should be 10uF minimum. Small ESR should be used to reduce output
ripple voltage. However, the best ESR may depend on L, capacitance, wiring and applications(output load).
Therefore, fully evaluate ESR under an actual condition to determine the best value.
4. External transistor (Q1 R1 C2)
An enhancement N-channel MOSFET or a bipolar NPN transistor can be used as the external switch transistor.
*Bipolar NPN transistor
The hFE value of NPN transistor and the R1 value determine the driving capacity to increase the output
current using a bipolar transistor. 1KΩ is recommended for R1. R1 is selected from the following calculation.
Calculate the necessary base current(Ib) from the bipolar transistor hFE using
R1 =
Ib =
I PK
hFE
Vout − 0.7
0.4
−
Ib
| I EXTH |
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QW-R502-099,A
L3380
CMOS IC
EXTERNAL COMPONENTS(Cont.)
Since the pulse current flows through the transistor, the exact Rb value should be finely tuned by the
experiment. Generally, a small Rb value can increase the output current capability, but the efficiency will
decrease due to more energy is used to drive the transistor.
Moreover, a speed up capacitor, C2, should be connected in parallel with R1 to reduce switching loss and
improve efficiency. C2 can be calculated by the equation below:
C2 ≤
1
2π × R1× fOSC × 0.7
It is due to the variation in the characteristics of the transistor used. The calculated value should be used as
the initial test value and the optimized value should be obtained by the experiment.
*Enhancement MOS FET
For enhancement N-channel MOSFET, since enhancement MOSFET is a voltage driven, it is a more efficient
switch than a BJT transistor. However, the MOSFET requires a higher voltage to turn on as compared with BJT
transistors. An enhancement N-channel MOSFET can be selected by the following guidelines:
-Input capacitance less than 700pF.
-Low gate threshold voltage.
-Low on-resistance.
-The allowable maximum current of drain should be larger than peak current of inductor.
UTC assumes no responsibility for equipment failures that result from using products at values that
exceed, even momentarily, rated values (such as maximum ratings, operating condition ranges, or
other parameters) listed in products specifications of any and all UTC products described or contained
herein. UTC products are not designed for use in life support appliances, devices or systems where
malfunction of these products can be reasonably expected to result in personal injury. Reproduction in
whole or in part is prohibited without the prior written consent of the copyright owner. The information
presented in this document does not form part of any quotation or contract, is believed to be accurate
and reliable and may be changed without notice.
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