10 Rx126PA035SC M620F4x D1 19

10-RZ126PA035SC-M620F41
10-R0126PA035SC-M620F40
Output Inverter Application
flow 90PACK 0
1200V/35A
General conditions
3phase SPWM
VGEon = 15 V
VGEoff = -15 V
Rgon = 16 Ω
Rgoff = 16 Ω
IGBT
Figure 1
FWD
Figure 2
Typical average static loss as a function of output current
Ploss = f(Iout)
Typical average static loss as a function of output current
Ploss = f(Iout)
Ploss (W)
90
Ploss (W)
100
Mi*cosfi = 1
75
80
Mi*cosf i= -1
60
60
45
40
30
20
15
Mi*cosfi = 1
Mi*cosfi = -1
0
0
0
10
20
30
40
50
60
0
70
10
20
30
40
50
60
Iout (A)
At
Tj =
150
70
Iout (A)
At
Tj =
°C
Mi*cosφ from -1 to 1 in steps of 0,2
150
°C
Mi*cosφ from -1 to 1 in steps of 0,2
IGBT
Figure 3
Typical average switching loss
as a function of output current
FWD
Figure 4
Typical average switching loss
as a function of output current
Ploss = f(Iout)
Ploss = f(Iout)
30
Ploss (W)
Ploss (W)
100
fsw = 16kHz
25
fsw = 16kHz
80
20
60
15
40
10
20
5
fsw = 2kHz
fsw = 2kHz
0
0
0
10
20
30
40
At
Tj =
150
DC link =
fsw from
600
V
2 kHz to 16 kHz in steps of factor 2
copyright by Vincotech
50
60 Iout (A)
0
70
°C
1
10
20
30
40
At
Tj =
150
DC link =
fsw from
600
V
2 kHz to 16 kHz in steps of factor 2
50
60
Iout (A)
70
°C
Revision: 1
10-RZ126PA035SC-M620F41
10-R0126PA035SC-M620F40
Output Inverter Application
flow90PACK 0
Phase
Figure 5
Typical available 50Hz output current
as a function Mi*cosφ
Phase
Figure 6
Typical available 50Hz output current
as a function of switching frequency
Iout = f(Mi*cos φ)
Iout (A)
60
Iout (A)
1200V/35A
Th = 60°C
50
Iout = f(fsw)
60
50
Th = 60°C
40
40
Th = 100°C
30
30
20
20
Th = 100°C
10
10
0
0
-1,0
-0,8
-0,6
-0,4
-0,2
0,0
0,2
At
Tj =
150
DC link =
fsw =
Th from
600
V
4
kHz
60 °C to 100 °C in steps of 5 °C
0,4
0,6
0,8
1,0
Mi*cos φ
1
At
Tj =
°C
10
150
fsw (kHz)
100
°C
DC link = 600
V
Mi*cos φ = 0,8
Th from
60 °C to 100 °C in steps of 5 °C
Phase
Figure 7
Typical available 0Hz output current as a function
Ioutpeak = f(fsw)
of switching frequency
-1,0
45,0-50,0
50
Iout (Apeak)
-0,8
Mi*cosfi
Iout (A)
-0,6
40,0-45,0
Phase
Figure 8
Typical available 50Hz output current as a function of
Iout = f(fsw, Mi*cos φ)
Mi*cos φ and switching frequency
40
-0,4
Th = 60°C
35,0-40,0
-0,2
30,0-35,0
30
0,0
25,0-30,0
0,2
20,0-25,0
20
0,4
15,0-20,0
0,6
10
Th = 100°C
10,0-15,0
0,8
1,0
1
2
4
8
16
32
0
64
1
fsw (kHz)
10
At
Tj =
150
°C
At
Tj =
150
DC link =
Th =
600
80
V
°C
DC link =
Th from
600
V
60 °C to 100 °C in steps of 5 °C
Mi =
0
copyright by Vincotech
2
fsw (kHz)
100
°C
Revision: 1
10-RZ126PA035SC-M620F41
10-R0126PA035SC-M620F40
Output Inverter Application
flow90PACK 0
Inverter
Figure 9
Inverter
Figure 10
Typical available peak output power as a function of
Pout=f(Th)
heatsink temperature
Typical efficiency as a function of output power
efficiency=f(Pout)
efficiency (%)
25
Pout (kW)
1200V/35A
2kHz
100
20
99
15
98
2kHz
16kHz
10
97
16kHz
96
5
95
0
60
70
80
90
At
Tj =
150
DC link =
Mi =
cos φ=
fsw from
600
V
1
0,80
2 kHz to 16 kHz in steps of factor 2
o
Th ( C)
0
100
°C
5
10
15
20
At
Tj =
150
DC link =
Mi =
cos φ=
fsw from
600
V
1
0,80
2 kHz to 16 kHz in steps of factor 2
25
30
35
Pout (kW)
°C
Inverter
Figure 11
Overload (%)
Typical available overload factor as a function of
Ppeak / Pnom=f(Pnom,fsw)
motor power and switching frequency
550
500
450
400
350
300
250
200
Switching frequency (kHz)
150
Motor nominal power (HP/kW)
100
5,00 / 3,68
7,50 / 5,52
10,00 / 7,36
15,00 / 11,03
20,00 / 14,71
25,00 / 18,39
1
524
349
262
175
131
0
2
524
349
262
175
131
0
4
521
348
261
174
130
0
8
444
296
222
148
111
0
16
331
221
166
110
0
0
At
Tj =
150
°C
DC link =
Mi =
600
1
V
cos φ=
fsw from
Th =
0,8
1 kHz to 16kHz in steps of factor 2
80
°C
Motor eff = 0,85
copyright by Vincotech
3
Revision: 1
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