Chenmko CHEMG2PT Dual digital silicon transistor Datasheet

CHENMKO ENTERPRISE CO.,LTD
CHEMG2PT
SURFACE MOUNT
Dual Digital Silicon Transistor
VOLTAGE 50 Volts
CURRENT 30 mAmpere
APPLICATION
* Switching circuit, Inverter, Interface circuit, Driver circuit.
FEATURE
SOT553
* Small surface mounting type. (SOT-553)
* High current gain.
* Suitable for high packing density.
*
*
*
*
Low colloector-emitter saturation.
High saturation current capability.
Two CHDTC144E transistors in one package.
Built in bias resistor(R1=47kΩ, Typ. )
(4)
(3)
0.50
0.9~1.1
0.50
0.15~0.3
(5)
MARKING
1.5~1.7
(1)
1.1~1.3
* G2
0.5~0.6
0.19~0.18
1.5~1.7
CIRCUIT
3
2
R2
1
R1
R1
R2
4
5
SOT553
Dimensions in millimeters
LIMITING VALUES
In accordance with the Absolute Maximum Rating System (IEC 60134).
SYMBOL
PARAMETER
CONDITIONS
MIN.
MAX.
UNIT
VCC
Supply voltage
−
50
V
VIN
Input voltage
-10
+40
V
−
30
−
100
−
200
mW
O
C
IO
DC Output current
IC(Max.)
Tamb ≤ 25 OC, Note 1
mA
PTOT
Total power dissipation
TSTG
Storage temperature
−55
+150
TJ
Junction temperature
−
150
O
C
Thermal resistance
−
625
O
C/W
RθJ-A
Note
1. Transistor mounted on an FR4 printed-circuit board.
junction - ambient air
2004-07
RATING CHARACTERISTIC ( CHEMG2PT )
CHARACTERISTICS
Tamb = 25 °C unless otherwise speciÞed.
SYMBOL
PARAMETER
CONDITIONS
MIN.
TYP.
MAX.
UNIT
VIoff)
Input off voltage
IO=100uA; VCC=5.0V
0.5
−
−
VI(on)
Input on voltage
IO=2mA; VO=0.3V
−
−
3.0
V
VO(on)
Output voltage
IO=10mA; II=0.5mA
−
−
0.3
V
II
Input current
VI=5V
−
−
0.18
mA
IC(off)
Output current
VI=0V; VCC=50V
−
−
0.5
uA
hFE
DC current gain
IO=5mA; VO=5.0V
68
−
−
R1
Input resistor
32.9
47
61.1
KΩ
R2/R1
fT
Resistor ratio
Transition frequency
0.8
−
1.0
250
1.2
−
MHz
Note
1.Pulse test: tp≤300uS; δ≤0.02.
IE=-5mA, VCE=10.0V
f=100MHz
=
RATING CHARACTERISTIC CURVES ( CHEMG2PT )
Typical Electrical Characteristics
Fig.1 Input voltage vs. output current
(ON characteristics)
100
Fig.2 Output current vs. input voltage
(OFF characteristics)
10m
5m
VO=0.3V
OUTPUT CURRENT : Io (A)
INPUT VOLTAGE : VI(on) (V)
50
20
10
5
Ta =- 40OC
O
25
= C
100OC
2
1
500m
200m
100m
100
200
500 1m
2m
2m
1m
500
VCC=5V
Ta=100OC
25OC
-40 OC
200
100
50
20
10
5
2
1
5m 10m 20m 50m 100m
0
0.5
OUTPUT CURRENT : IO (A)
Fig.3 DC current gain vs. output
current
1k
1
VO =5V
2.0
2.5
3.0
lO/lI=20
500m
OUTPUT VOLTAGE : VO(on) (V)
DC CURRENT GAIN : GI
100
1.5
Fig.4 Output voltage vs. output
current
500
200
1.0
INPUT VOLTAGE : VI(off) (V)
Ta=100OC
25OC
-40OC
50
20
10
5
2
1
100 200
200m
100m
Ta=100OC
25OC
-40 OC
50m
20m
10m
5m
2m
500 1m 2m
5m 10m 20m 50m100m
OUTPUT CURRENT : IO (A)
1m
100
200
500 1m
2m
5m 10m 20m 50m 100m
OUTPUT CURRENT : IO (A)
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