STMicroelectronics AN444 Dissipation power and surge current duration Datasheet

AN444
APPLICATION NOTE
TRANSISTOR PROTECTION BY TRANSIL:
DISSIPATION POWER AND SURGE CURRENT DURATION
INTRODUCTION
In a great number of applications, we find the diagram in Figure 1 where a Transil is used to protect a
switch which controls an inductive load.
The switch can be a bipolar or a MOS transistor.
The purpose of this paper is to calculate the dissipated power in the Transil and the pulse current duration.
Figure 1. Basic Diagram
VCC
L, r
OR
CIRCUIT MODELISATION
When the switch turns off we use the equivalent circuit represented in Figure 2.
The worst case is to consider VCL = VBR min.
This hypothesis will be used in all formulas.
Figure 2. Equivalent Circuit
L
r
VCC
rd
VCL
VBR
VCL = VBRmin
Note: VCL: clamping voltage;
VBR: breakdown voltage;
rd: apparent resistance.
April 2004
Rev. D2A - 3582
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AN444 APPLICATION NOTE
CURRENT IN THE TRANSIL
We can express the current i through the Transil by the following formula:
V BR min – V CC
V BR min – V CC
t
i =  I p + -------------------------------------- exp  – r --- + -------------------------------------



L
r
r
Ip is the current through the coil when the transistor switches off. Figure 3 shows the current variation versus time.
Figure 3. Current Waveform
Ip
t1
t
VCC-VBR
r
t1 can be calculated by:
V BR min – V CC
t1 = – L
--- ln  ----------------------------------------------------
V BR min – V CC – rI p
r
TRANSIL POWER DISSIPATION
We can consider two cases, single pulse operation and repetitive pulses operation.
Single pulse operation
In this case, in order to define a Transil we need peak power Pp and the pulse current standard duration tp.
Pp is given by Pp = VBR min x Ip.
If we assimilate the pulse current with a triangle the standard exponential pulse duration tp is calculated
by the formula:
V BR min – V CC
1.4L
tp = –  ------------ ln  ----------------------------------------------------
 2r   V BR min – V CC + rI p
The energy in the Transil can be expressed by:
V BR min – V CC  V BR min – V CC 
V BR min ⋅ L
- ln ---------------------------------------------------- [ I p +  -------------------------------------W = ---------------------------
  V BR min – V CC + rI p
r
r
When r tends to zero we find:
V BR min
1 2
W = --- LI p  ---------------------------------------
 V BR min – V CC
2
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AN444 APPLICATION NOTE
Repetitive pulses operation
In repetitive pulse operation the power dissipation can be calculated by the following formula:
V BR min ⋅ L
V BR min – V CC
V BR min – V CC
P = F × ----------------------------- [ I p +  --------------------------------------- ln  ----------------------------------------------------



r
r
V BR min – V CC + rI p
When r tends to zero we find:
V BR min
2
1
P = --- LFI p  ---------------------------------------
 V BR min – V CC
2
Where F is the commutation frequency.
EXAMPLE OF APPLICATION
Commutation of a coil supplied by a battery. The different parameters of the application are:
VCC = 14V; L = 10mH; r = 3Ω; Ip = 4A.
Transil: 1.5KE36P VBRmin = 34.2V (cf data sheet).
Single pulse
We find:
Pp = 34.2 x 4 = 136.8W
–3
– 1.4 ⋅ 10 ⋅ 10
34.2 – 14
tp = –  --------------------------------------- ln  -------------------------------------------



34.2 – 14 + 3 × 4
2×3
tp = 1.08ms
The data sheet gives Pp 1500W for tp = 1.08ms then this 1.5KE36P can be used in this application.
Repetitive pulse operation
The commutation frequency is equal to 10Hz so:
–3
34.2 ⋅ 10 ⋅ 10
34.2 – 14
34.2 – 14
P = 10 × --------------------------------------- [ 4 +  --------------------- ln  -------------------------------------------

  34.2 – 14 + 3 × 4
3
3
P = 980mW.
Rth = 75°C/W and Tj max = 175°C.
So Tj = P x Rth + Tambmax.
With Tambmax = 50°C we find:
Tj = 0.98 x 75 + 50 = 123.5°C < Tj max
So we can also use this Transil in repetitive pulse operation.
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AN444 APPLICATION NOTE
REVISION HISTORY
Table 1. Revision History
4/5
Date
Revision
Description of Changes
May-1992
1
First Issue
16-Apr-2004
2
Stylesheet update. No content change.
AN444 APPLICATION NOTE
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