30-F2127PA075SC-L178E09 Output Inverter Application flow 7PACK 2 1200 V / 75 A General conditions 3phase SPWM V GEon = 15 V V GEoff = -15 V R gon = 4 Ω R goff = 4 Ω Figure 1 IGBT Figure 2 Typical average static loss as a function of output current P loss = f(I out) 140 Ploss (W) 200 Ploss (W) FWD Typical average static loss as a function of output current P loss = f(I out) Mi*cosfi = 1 180 120 160 Mi*cosf i= -1 100 140 120 80 100 60 80 60 40 40 20 20 Mi*cosfi = -1 Mi*cosfi = 1 0 0 0 20 40 60 80 100 120 0 140 20 40 60 80 100 120 Iout (A) At Tj = 150 At Tj = °C Mi*cosφ from -1 to 1 in steps of 0,2 150 °C Mi*cosφ from -1 to 1 in steps of 0,2 Figure 3 IGBT Typical average switching loss as a function of output current Figure 4 FWD Typical average switching loss as a function of output current P loss = f(I out) 200,0 Ploss (W) Ploss (W) 140 Iout (A) fsw = 16kHz 180,0 P loss = f(I out) 60,0 fsw = 16kHz 50,0 160,0 140,0 40,0 120,0 30,0 100,0 80,0 20,0 60,0 40,0 10,0 20,0 fsw = 2kHz fsw = 2kHz 0,0 0,0 0 20 40 60 80 100 120 0 140 20 40 60 80 100 Iout (A) At Tj = 150 140 Iout (A) At Tj = °C DC link = 600 V f sw from 2 kHz to 16 kHz in steps of factor 2 copyright Vincotech 120 150 °C DC link = 600 V f sw from 2 kHz to 16 kHz in steps of factor 2 1 27 Jul. 2015 / Revision 1 30-F2127PA075SC-L178E09 Output Inverter Application flow 7PACK 2 Figure 5 Phase Figure 6 Typical available 50Hz output current as a function Mi*cosφ I out = f(Mi*cos φ ) Phase Typical available 50Hz output current as a function of switching frequency I out = f(f sw) Iout (A) 120 Iout (A) 1200 V / 75 A Th = 60°C 100 120 Th = 60°C 100 80 80 Th = 100°C 60 60 40 40 20 Th = 100°C 20 0 -1,0 -0,8 -0,6 -0,4 -0,2 0,0 0,2 0,4 0,6 0,8 0 1,0 1 10 100 Mi*cos φ At Tj = 150 fsw (kHz) At Tj = °C DC link = 600 V f sw = 4 kHz T h from 60 °C to 100 °C in steps of 5 °C 150 °C DC link = 600 V Mi*cos φ =0,8 T h from 60 °C to 100 °C in steps of 5 °C Figure 7 Phase Figure 8 Typical available 50Hz output current as a function of Mi*cos φ and switching frequency I out = f(f sw, Mi*cos φ ) Iout (Apeak) -1,00 -0,80 Iout (A) -0,60 95,0-110,0 Phase Typical available 0Hz output current as a function of switching frequency I outpeak = f(f sw) 120 Th = 60°C 100 -0,40 80 80,0-95,0 65,0-80,0 0,00 50,0-65,0 Mi*cosfi -0,20 60 0,20 35,0-50,0 40 0,40 20,0-35,0 0,60 20 Th = 100°C 0,80 0 1,00 1 At Tj = 2 4 8 fsw 16 32 1 64 10 100 fsw (kHz) 150 °C At Tj = DC link = 600 Th = 80 V °C DC link = 600 V T h from 60 °C to 100 °C in steps of 5 °C Mi = copyright Vincotech 2 150 °C 0 27 Jul. 2015 / Revision 1 30-F2127PA075SC-L178E09 Output Inverter Application flow 7PACK 2 Figure 9 Inverter Figure 10 Inverter Typical efficiency as a function of output power efficiency=f(Pout) efficiency (%) Pout (kW) Typical available peak output power as a function of heatsink temperature P out=f(T h) 60,0 50,0 1200 V / 75 A 2kHz 100,0 99,0 2kHz 98,0 97,0 40,0 96,0 30,0 16kHz 95,0 94,0 16kHz 20,0 93,0 92,0 10,0 91,0 0,0 50 55 60 65 70 75 80 85 90 95 90,0 100 0,0 10,0 20,0 30,0 40,0 50,0 Th (oC) At Tj = 150 DC link = Mi = cos φ= f sw from 600 V 1 0,80 2 kHz to 16 kHz in steps of factor 2 70,0 Pout (kW) °C Figure 11 60,0 At Tj = 150 DC link = Mi = cos φ= f sw from 600 V 1 0,80 2 kHz to 16 kHz in steps of factor 2 °C Inverter Overload (%) Typical available overload factor as a function of motor power and switching frequency P peak / P nom=f(P nom,fsw) 400 350 300 250 200 150 Switching frequency (kHz) 100 Motor nominal power (HP/kW) 15,00 / 11,03 20,00 / 14,71 25,00 / 18,39 30,00 / 22,07 40,00 / 29,42 50,00 / 36,78 1 374 281 225 187 140 112 2 374 281 225 187 140 112 4 374 281 225 187 140 112 8 322 241 193 161 121 0 16 241 181 145 121 0 0 At Tj = 150 DC link = Mi = cos φ= f sw from Th = 600 V 1 0,8 1 kHz to 16kHz in steps of factor 2 80 °C °C Motor eff =0,85 copyright Vincotech 3 27 Jul. 2015 / Revision 1