IPS401 Application Note (82.13 kB)

AN-IPS-08 Revision 1
DC Input Boost Converters with IPS401
(Boost – Tapped Boost – Flyback Topologies for LED Control Solutions)
IN-PLUG® Team
July 11, 2007
Introduction
This is a collection of information to assist in understanding the design of LED driver circuits using the
IPS401 in a class of variable frequency DC input converters.
Topology choices
There is a very wide array of power conversion topologies, each with its unique aspects. Most designs use
pulse width modulation of the power switch duty cycle to vary the power supply performance to adapt to
varying input voltage or output load. The terminology describing these converters subdivides them into
discontinuous, critical, and continuous current mode converters. This discussion will be about topologies
that use a variable operating frequency, with continuous current conduction provided by the IPS401. The
defining aspect of these converters is that the current variation is a fixed amount, specifically, with a twoto-one ratio. The most basic implementation is a non-isolated boost converter.
Alternatives to the boost are the tapped-boost and the flyback. Each of these alternatives uses a two
winding transformer in place of the boost inductor. The applications targeted are still non-isolated, and the
solution still results in varying both the frequency and duty cycle. The turns ratio of the transformer allows
for a wider range of output voltages with the duty cycle ‘centered’ more towards 50%.
Boost Topology
A boost converter (shown below) creates an output voltage greater than the input voltage.
In the proposed scheme, the FET switching is controlled such that the current through the inductor is
continuous, and the current at the beginning of the on-state is half the current at the end of the on-state. It
can also be described as: the current at the beginning of the off-state is twice the current at the end of the
off-state.
L
VOUT+
D
DCSource
+
Q
C
C
|
VOUT-
© Copyright 2007 - ASIC Advantage, Inc. – All rights reserved
- Revision 1 – July 11, 2007
1/8
Application Note AN-IPS-08 – Rev1– IPS401 LED Controller in Various Boost Topologies–
A typical plot of the inductor current versus time would look like:
Note that the bottom of the plot is zero amps, with the sawtooth going between one and two amps.
Boost equations
Let I1 be the inductor current at the beginning of the on-time (the valley) and I2 is the current at the end of
the on-time (the peak).
From the definition of this control scheme: I2 = 2*I1
The power being converted is the energy-per-cycle times the cycles-per-second. The energy in an inductor
is E = 0.5*L*I 2 . The power is therefore
P = [0.5*L*I2 2 - 0.5*L*I1 2 ]*f. = 0.5*L*(I2 2 -I1 2 )*f = 0.5*L*([4* I1 2 -I1 2 )*f
= 1.5*L* I1 2 * f
The change in current during the on-time is I2-I1 = I1, the voltage across the inductor during the on-time is
L * I1
.
Vin, so the on-time is Ton =
Vin
The change in current during the off-time is I1 as well, the voltage across the inductor during the off-time
L * I1
is (Vout – Vin), so the off-time is Toff =
.
Vout − Vin
1
1
1
The operating frequency is f =
=
=
=
L * I1
L * I1
T
Ton + Toff
+
Vin Vout − Vin
Vin * (Vout − Vin)
Vin * (Vout − Vin)
=
L * I1 * (Vout − Vin) + L * I1 * Vin
L * I1 * Vout
© Copyright 2007 - ASIC Advantage, Inc. – All rights reserved
- Revision 1 – July 11, 2007
2 / 10
Application Note AN-IPS-08 – Rev1– IPS401 LED Controller in Various Boost Topologies–
The duty cycle is D =
Ton
L * I1 Vin * (Vout − Vin) Vout − Vin
*
= Ton * f =
=
T
Vin
L * I1 * Vout
Vout
The voltage transfer ratio is derived from applying volt-seconds balance to the inductor.
Vin * D = (Vout – Vin)*(1-D) = (1-D)*Vout - Vin + D*Vin
1 = (1-D)*Vout – Vin
Vin = (1-D)*Vout
1
Vout
A plot of this equation is shown below as part of the tapped boost.
=
M=
Vin
1− D
Boost discussion
The boost is the simplest of the topologies discussed here. The input current is continuous (hence the name
‘continuous conduction mode”), and the output current is discontinuous. The output voltage has to be equal
to or greater than the input voltage. The FET and diode both experience a peak voltage of the output
voltage, and both see the same peak current. This can necessitate an expensive FET/diode pair in the cases
where there is a high amount of boost. For example: if the application is for 450 volts output and 12 volts
input, the average input current (and hence the peak input current) will be large because of the
comparatively low input voltage, and both the FET and diode need to be rated for 450 volts, even though
the input voltage is only 12 volts. The duty cycle here would be D = (450-12)/450 = 438/450 = 97.3%.
Limitations in the speed of the FET drive will limit the maximum frequency because the off-time will be so
short.
Tapped Boost Topology
Adding an extra winding to the boost inductor allows the on-time and off-time inductances to be selected
independently. This can also be viewed as adding a turns-ratio to the design. It will still act as a boost, and
it is still not isolated. During the off-time the input current still flows directly to the output. This last
comment is what distinguishes this from a flyback. This means that the ‘primary’ winding gets better
utilization than in a flyback. The component stresses are changed from the simple boost, some to advantage
and some not.
Basic topology
L1
L2
o
o
VOUT+
D1
DCSource
+
Q1
C2
C1
|
VOUT-
© Copyright 2007 - ASIC Advantage, Inc. – All rights reserved
- Revision 1 – July 11, 2007
3 / 10
Application Note AN-IPS-08 – Rev1– IPS401 LED Controller in Various Boost Topologies–
The inductance of L2 is typically greater than that of L1, and they are on one magnetic core with the dot
polarity as shown. During the switch on-time, energy is stored in inductance L1. There is no current in L2
because the diode is reverse biased (by a voltage greater than the output voltage because the voltage on L2
is equal the voltage on L1 times the turns ratio). During the off-time, when the FET is an open-circuit, the
total inductance of L1 and L2 transfers the stored energy to the output.
It is important to remember that inductance is proportional to the square of the number of turns. So, for
example, if the turns-ratio is 10 (number of L2 turns is ten times that of L1), the inductance of L2 is 100
times that of L1. And also remember that the total inductance of L1 and L2 during the off-time, as shown,
is NOT just L1+L2, because there is coupling between them and the aforementioned square-law relation.
So, using this same 10x turns ratio example, the effective total inductance seen during the off-time is 11 x
11 = 121 (one plus the turns ratio squared) times the inductance of L1.
Tapped boost equations
The basic input-output voltage relation is derived from inductor volt-seconds balance, as previously done
for the boost. Here, the equation for volt-seconds is balanced across the L1 winding. N1 is the number of
L1 turns, and N2 is the number of L2 turns.
Vin * D = (Vout – Vin)*(1-D)*
N1
Vout
, solving for Vout, and then for
N1 + N 2
Vin
(1 − D) * Vin * N1
Vout * (1 − D) * N1
= Vin*D +
N1 + N 2
N1 + N 2
M=
Vout
=
Vin
(1 − D) * N1
N2* D
1+
N1 + N 2 = 1 * ⎡ D * ( N1 + N 2) + (1 − D )⎤ =
N1
⎥⎦
(1 − D) * N1
1 − D ⎢⎣
1− D
N1
N1 + N 2
D+
If N2=0, then you have a conventional boost, and the voltage ratio reverts to that of the boost. So, it can be
N2* D⎞
⎛
said that the tapped boost changes the output voltage by a factor of ⎜1 +
⎟ . Some examples of this
N1 ⎠
⎝
voltage ratio are shown below.
© Copyright 2007 - ASIC Advantage, Inc. – All rights reserved
- Revision 1 – July 11, 2007
4 / 10
Application Note AN-IPS-08 – Rev1– IPS401 LED Controller in Various Boost Topologies–
Voltage Transfer Ratio
14
13
12
11
10
M(D)
9
8
Boost, N2=0
7
N2=N1
6
N2=2*N1
5
4
3
2
1
0
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
Duty Cycle
For analyzing the currents, the designer must remember that because the on-time and off-time inductances
are different, the input current is continuous, but it changes amplitude abruptly whenever the FET switches.
It goes through a jump downwards when the FET turns off, and likewise a jump upwards when the FET
turns on. From the definition of this control scheme, the maximum input current is twice the minimum
input current. Also, the peak output current is twice the output current at the end of the off-time. Since
designs typically are done off of output specifications, the below calculation will start with the output
current. The average output current is the time average of the off-state current, or:
Iout,max = 2*Iout,min
Iout,ave = (1-D) *
Iout , max + Iout , min
= (1-D)*1.5*Iout,min
2
The average input current is the time average of the on-state current, plus the average output current, or:
Iin,max = 2*Iin,min
Iin,ave = Iout,ave + D*
In, max + Iin, min
= Iout,ave + D*1.5*Iin,min
2
Using the inductances, where Ltotal is the effective total inductance seen during the off-time:
Toff =
Ltotal * ( Iout , max − Iout , min)
Ltotal * Iout , min
=
Vout − Vin
Vout − Vin
© Copyright 2007 - ASIC Advantage, Inc. – All rights reserved
- Revision 1 – July 11, 2007
5 / 10
Application Note AN-IPS-08 – Rev1– IPS401 LED Controller in Various Boost Topologies–
L1 * ( Iin, max − Iin, min)
L1 * Iin, min
=
Vin
Vin
1
Freq =
Ton + Toff
Ton =
Power = 1.5 * L1 * Iin,min 2 * Freq
Current sensing
The IPS401 requires that the input and output current be sensed, and sensed at the same scale (continuous
current waveform) in order to find the “halfway points”). A single resistor will not work here, because
neither the input nor output current is a straightforward continuous sawtooth waveform. An additional
current sense resistor is needed to allow the different on-time and off-time current amplitudes to be
combined into a well-behaved sawtooth. An example of that wiring is shown below. Note that the ground
pin for the IPS401 is the output ground. Since this is a boost configuration, the input current will be greater
than the output current. The IS (switched current sense) pin senses a negative voltage with respect to chip
ground. During the on-time, there will be no current in R2, and the on-state current will be sensed by the
voltage drop across R1. During the off-time, there will be no current through the FET, and the current will
be sensed by the voltage drop across R1+R2. For most uses of this configuration, R2 is equal to R1 times
the turns ratio.
L1
L2
o
o
DCSource
VOUT+
D
U1
+
1
2
C
|
3
4
GND
IS
BYPASS
COMP
GDRV LEDSNS
VLINE
VCC
8
7
Q
C
6
5
IPS401
VOUT-
R1
R2
Tapped boost discussion
A tapped-boost transformer will be a little larger than the boost inductor for the same output power.
Another difference in component choice between the two topologies is the voltage rating of the output
diode. In the boost, the output diode sees a reverse voltage equal to the output voltage. In the tapped boost,
the reverse voltage is the output voltage plus the input voltage times the turns ratio. Conversely, and to the
benefit of the tapped boost topology, the maximum voltage across the FET is the input voltage plus the
output voltage minus the input voltage divided by one plus the turns ratio. As an example of these
statements, using again a turns ratio of 10, an input voltage of 12 volts and an output of 450 volts: the
maximum output diode reverse voltage will be 450 + 10*12 = 570 volts. The maximum FET voltage will
(450 − 12)
be 12 +
= 51.8 volts. If the output power is such that R1 is 0.2 ohm, then R2 is 2.2 ohms.
(10 + 1)
© Copyright 2007 - ASIC Advantage, Inc. – All rights reserved
- Revision 1 – July 11, 2007
6 / 10
Application Note AN-IPS-08 – Rev1– IPS401 LED Controller in Various Boost Topologies–
Detailed tapped boost design: 36W, 12-28V DC input, 450V DC out
A 10-to-1 turns ratio was chosen as a compromise between getting a duty cycle centered on 50% and
reverse voltage on the diode. The primary inductance chosen is 165 microhenries. The expected component
stresses in this design are:
Maximum FET voltage (28 V input) = 70 volts
Maximum FET current (12 V input) = 5 amps
Maximum diode reverse voltage (28 V input) = 770 volts
Maximum frequency = 88 kHz
Transformer design
A PQ3230 ferrite core is a reasonable choice to keep the flux density to 0.2 tesla. 26 turns of 16 AWG wire
on L1 and 260 turns of 30 AWG wire on the L2 fill the window area when using a bobbin. The copper is
allocated in about a 70/30 split between the two windings (L1 gets more window area because it conducts
during both the on-time and the off-time). The wound transformer is gapped to 165 microhenries L1
inductance (equivalent to 20 millihenries of total inductance with the two windings in series). Due to the
comparatively low operating frequency, the lowest cost inductor would possibly be an iron powder variety.
L1
L2
1A/1000V/ultrafast
o
o
12-28 volts
VOUT+
D
+
R4
2000
Q
C1
C
|
Q1
2N2222
Q2
2N2222
R5
33
U1
1
2
3
4
GND
IS
BYPASS
COMP
GDRV LEDSNS
VLINE
VCC
8
D1
7
DIMMING
6
200k
5
R6
IPS401
VOUT0.22
R1
2.2
R2
C2
2200pF/50V
1000
R3
© Copyright 2007 - ASIC Advantage, Inc. – All rights reserved
- Revision 1 – July 11, 2007
7 / 10
Application Note AN-IPS-08 – Rev1– IPS401 LED Controller in Various Boost Topologies–
Flyback Topology
L3
L4
o
o
VOUT+
D2
DCSource
+
Q2
C4
C3
|
VOUT-
In some cases, inrush current through the boost or tapped boost inductor to the large output capacitor when
the input voltage is applied, can be a problem. Some applications need to be able to shut off the power from
the input if there is a short on the output. Or the output voltage needs to be lower than the input. At times
like these, a flyback topology might be the best selection. The buck and tapped buck topologies (not
discussed here) can also be considered for the low output voltage case. For a review of the current sense
resistor issues, please refer to the application note AN-IPS-07 http://www.in-plug.com/applinotes/AN-IPS07_rev2_April07.pdf.
Flyback equations
The definitions of the variables are: I1p = switch current at the start of the on time, I2p = switch current at
the end of the on time, I1s = secondary current at the beginning of the on time, I2s = secondary current at
the end of the on time, Lp = primary inductance, N = turns ratio primary to secondary, Ls = secondary
inductance, ton = switch on time, toff = switch off time, f = frequency, P = input/output power (assume
100% efficiency), Vo = output voltage, Io = output current, Vin = input voltage. The defining equations are
then:
2*I1p = I2p
2*I1s = I2s
P = Vo * Io
P = 0.5*Lp*(I2p^2 - I1p^2)*f
P = 0.5*Ls*(I2s^2 - I1s^2)*f
F = 1/(ton+toff)
Ton = Lp *(I2p – I1p) / Vin
Toff = Ls *(I2s – I1s) / Vo
Lp = N^2 * Ls
If all these equations are solved simultaneously, the following result can be obtained:
I1p = 2*Io*[Vo +(Vin/N)]/[3*Vin]
© Copyright 2007 - ASIC Advantage, Inc. – All rights reserved
- Revision 1 – July 11, 2007
8 / 10
Application Note AN-IPS-08 – Rev1– IPS401 LED Controller in Various Boost Topologies–
Note that this current is independent of the choice of inductance. The assumption here is that the designer
already knows Lp, N, Ls, Vin, Vo, and Io. Computing this value and back-substituting into the equations to
get I2p, f, ton, toff, I1s, and I2s gives the complete description of the operating point.
Like all flyback power supplies, a flyback requires some amount of snubbing of the voltage spike on the
FET drain in order to keep the voltage rating of the FET to an affordable number. At some point, it may be
desirable to go to a “two switch flyback”, which can reduce the voltage stress on the switch at the expense
of using two switches, two diodes, and a high-side driver (magnetic or semiconductor). Pictured below is
an example of the two switch approach. Note that the switches are driven on/off simultaneously, and all
leakage inductance energy is returned to the input bus.
L5
L6
Q4
o
o
VOUT+
D4
D5
DCSource
+
Q3
C7
C5
|
D6
VOUT-
© Copyright 2007 - ASIC Advantage, Inc. – All rights reserved
- Revision 1 – July 11, 2007
9 / 10
Application Note AN-IPS-08 – Rev1– IPS401 LED Controller in Various Boost Topologies–
The following is a brief overview of certain terms and conditions of sale of product. For a full and complete copy of all
the General Terms and Conditions of Sale, visit our webpage http://www.asicadvantage.com/terms.htm.
LIMITED WARRANTY
The product is warranted that it will conform to the applicable specifications and be free of defects for one year.
Buyer is responsible for selection of, use of and results obtained from use of the product. Buyer indemnifies and
holds ASIC Advantage, Inc. harmless for claims arising out of the application of ASIC Advantage, Inc.’s products to
Buyer’s designs. Applications described herein or in any catalogs, advertisements or other documents are for
illustrative purposes only.
CRITICAL APPLICATIONS
Products are not authorized for use in critical applications including aerospace and life support applications. Use of
products in these applications is fully at the risk of the Buyer. Critical applications include any system or device
whose failure to perform can result in significant injury to the user.
LETHAL VOLTAGES
Lethal voltages could be present in the applications. Please comply with all applicable safety regulations.
INTELLECTUAL PROPERTY RIGHTS AND PROPRIETARY DATA
ASIC Advantage, Inc. retains all intellectual property rights in the products. Sale of products does not confer on
Buyer any license to the intellectual property. ASIC Advantage, Inc. reserves the right to make changes without
notice to the products at any time. Buyer agrees not to use or disclose ASIC Advantage Inc.’s proprietary
information without written consent.
TRADEMARKS AND PATENTS
- IN-PLUG® is a registered trademark of ASIC Advantage, Inc.
- AAI’s modified snubber network is patented under the US Patent # 6,233,165. IN-PLUG® Customers are granted
a royalty-free license for its utilization, provision the parts are purchased factory direct or from an authorized agent.
PROTECTION FOR CUSTOM IN-PLUG® SOLUTIONS
When AAI accepts to design and manufacture IN-PLUG® products to Buyer’s designs or specifications, buyer has
certain obligations to provide defense in a suit or proceeding claiming infringement of a patent, copyright or
trademark or for misappropriation of use of any trade secrets or for unfair competition.
COMPLIANCE WITH LAWS
Buyer agrees that at all times it will comply with all applicable federal, state, municipal, and local laws, orders and
regulations. Buyer agrees to comply with all applicable restrictions on exports and re-exports including obtaining any
required U.S. Government license, authorization, or approval. Buyer shall pay any duties, levies, taxes, brokerage
fees, or customs fees imposed on the products.
TITLE AND DELIVERY
All shipments of goods shall be delivered ExWorks, Sunnyvale, CA, U.S.A. Title in the goods shall not pass to Buyer
until ASIC Advantage, Inc. has received in full all amounts owed by Buyer.
LATEST DATASHEET UPDATES
For the latest datasheet updates, visit our web page: http://www.in-plug.com/datasheets.htm.
WORLDWIDE REPRESENTATIVES
To access AAI’s list of worldwide representatives , visit our web page http://www.in-plug.com/representatives.htm
COPYRIGHTS
Copyrights and all other proprietary rights in the Content rests with ASIC Advantage Inc. (AAI) or its
licensors. All rights in the Content not expressly granted herein are reserved. Except as otherwise provided,
the Content published on this document may be reproduced or distributed in unmodified form for personal
non-commercial use only. Any other use of the Content, including without limitation distribution,
reproduction, modification, display or transmission without the prior written consent of AAI is strictly
prohibited. All copyright and other proprietary notices shall be retained on all reproductions.
ASIC Advantage INC.
1290-B Reamwood Ave, Sunnyvale California 94089, USA
Tel: (1) 408-541-8686 Fax: (1) 408-541-8675
Websites: http://www.in-plug.com - http://www.asicadvantage.com
© Copyright 2007 - ASIC Advantage, Inc. – All rights reserved
- Revision 1 – July 11, 2007
10 / 10