ON MRA4005T1 Low-cost 100 ma high-voltage buck and buck-boost using ncp1052 Datasheet

AND8098/D
Low−Cost 100 mA
High−Voltage Buck and
Buck−Boost Using NCP1052
Prepared by: Kahou Wong
ON Semiconductor
http://onsemi.com
APPLICATION NOTE
INTRODUCTION
PRINCIPLE OF OPERATION
This application note presents low-cost high-voltage
100 mA non-isolated power supply using NCP1052 by
buck and buck-boost topology. The NCP1052 is one of the
latest low-cost switching controllers with integrated 700 V/
300 mA power switch from ON Semiconductor. It is
primarily designed for isolated 10 W-range flyback
converter. If isolation is not needed, the IC can also be used
as stepping-down buck and buck-boost converter for
further cost saving by removing optocoupler and replacing
the transformer by an inductor. The output current capability
is 100 mA. The possible operating range is from input range
between 20 Vdc and 700 Vdc to output range of 5.0 V or
above with 100 mA. Typical efficiency around 65% is
obtained in the 12 V buck demo board.
Advantages of the proposed circuits include:
• Comparing to flyback, buck and buck-boost eliminates
optocoupler and replaces transformer by an inductor for
cost saving.
• Buck and buck-boost offers smaller voltage stress in
switches comparing to flyback. It minimizes the
switching loss and increases efficiency.
• NCP105x can power up itself from the high input
voltage with wide range between 20 Vdc and 700 Vdc.
It needs no extra supply circuit.
• NCP105x operates at 44, 100, or 136 kHz and
accommodates low-cost components such as aluminum
electrolytic capacitors and powered-iron core magnetic.
• NCP105x offers frequency jittering for reduced
electromagnetic inference (EMI).
• NCP105x offers thermal and short circuit fault
protection.
• Simple design as no control-loop compensation is
concerned.
The proposed buck and buck-boost converters are very
similar to each other. Their major difference is that buck
provides a positive output voltage but buck-boost provides
a negative output voltage referring to the input ground.
Figure 1 shows the proposed buck and buck-boost
converters. The rectifier circuit, which consists of capacitor
C3 and diode D3, is in the front end for AC or DC input
voltage. Then, the NCP1052 is self-powered up from the
rectified input voltage directly with a VCC capacitor C2.
When the switch inside the IC is opened, there is a voltage
across Drain (D) and Source (S) pins of the IC. If this voltage
is greater than 20 V, an internal current source Istart = 6.3 mA
(typ.) inside the IC charges up C2 and a voltage in C2 is built
up for the operation of the IC. Comparing to the switching
frequency, the VCC voltage level is in a lower-frequency
7.5-8.5 V hysteresis loop. This VCC hysteresis loop is for
frequency jittering features to minimize EMI and
short-circuit fault timing function.
 Semiconductor Components Industries, LLC, 2003
June, 2003 - Rev. 1
D2 Z2
FB
D3
Input
D1
D
C1
S
VCC
C3
R1
L
D
C
Z1
Output
C
Z1
Output
C2
(a) Buck
D2 Z2
D3
Input
FB
D
S
C1
D
VCC
C3
D1
L
R1
C2
(b) Buck-boost
Figure 1. Proposed Circuit Using NCP1052
In Figure 2a it is noted that in the buck topology the input
voltage powers up the IC through the path across the
inductor L and capacitor C. This charging path passes
1
Publication Order Number:
AND8098/D
AND8098/D
through the output and a low-frequency ripple will be found
in the output voltage. Hence, the value of C2 is needed to be
small enough to increase this charging frequency fVCC in
order to reduce output voltage ripple because some
efficiency is lost due to this low-frequency ripple.
D2 Z2
D1
R1
Istart
FB
D3
Input
D
C1
S
VCC
C3
The function of diode D1, capacitor C1 and resistor R1 are
to transfer the magnitude of output voltage to a voltage
across C1 so that the IC can regulate the output voltage. In
Figure 3, when the main switch inside the IC is opened and
the diode D is closed. In buck, the potential of the IC
reference ground (pin S) becomes almost 0 V in this
moment. In buck-boost, the potential of the IC reference
ground (pin S) becomes -Vout in this moment. The voltage
in C1 will be charged to the output voltage. On the other
hand, when main switch is closed and the diode D is opened,
diode D1 is reverse biased by a voltage with magnitude Vin
and Vin+Vout respectively. Hence, D1 does not affect the
normal operation of the buck and buck-boost converter.
It is noted that the instantaneous voltage in C1 can be
possibly greater than the output voltage especially when
output current or output ripple is too large. It directly affects
the load regulation of the circuit since the IC regulates the
output voltage based on the voltage in C1. In order to solve
it, larger values of L and R1 can help to slow down the
charging speed of C1. It reduces the maximum instantaneous
voltage in C1 so that output voltage at high output current
can be pulled up and a good regulation is made.
Larger value of L can help the load regulation but it
usually unwanted because it is bulky. Hence, resistor R1 is
recommended. Larger value of R1 makes higher output
voltage. Hence, it is called as a “pull-up resistor” and it can
help to pull up the output voltage slightly.
The voltage in C1 representing the output voltage is
feedback to the feedback (FB) pin of the NCP1052 through
a diode D2 and zener diode Z2. When output voltage is too
high, there will be a greater-than-50 A current inserting
into the feedback pin of the NCP1052. The NCP1052 will
stop switching when it happens. When output voltage is not
high enough, the current inserting into the feedback is
smaller than 50 A. The NCP1052 enables switching and
power is delivered to the output until the output voltage is
too high again.
The purpose of the diode D2 is to ensure the current is
inserting into the feedback pin because the switching of
NCP1052 can also be stopped when there is a
greater-than-50 A current sinking from the FB pin. The
purpose of the zener diode Z2 is to set the output voltage
threshold. The FB pin of NCP1052 with a condition of
50 A sourcing current is about 4.3 V. The volt-drop of the
diode D2 is loosely about 0.7 V at 50 A. Hence, the output
voltage can be loosely set as follows:
L
D
C
Z1
Output
C
Z1
Output
C2
(a) Buck
D2 Z2
D1
Istart
D3
FB
D
S
D
VCC
Input
C3
C1
R1
L
C2
(b) Buck-boost
Figure 2. Charging Current of C2
In Figure 2b it is noted that in the buck-boost topology the
charging current path is blocked by diode D and hence the
charging of C2 does not affect the output voltage directly.
However, it still affects the output voltage indirectly and
slightly by adding some low-frequency noise on the
inductor. Hence, small value of C2 is also wanted.
D1
R1
C1
Vout
(a) Buck
D1
C1
Vout zener 4.3 V 0.7 V
zener 5 V
R1
(eq. 1)
According to (1), the possible minimum output voltage of
the circuit is 5.0 V when there is no zener diode Z2.
If there is no load, the IC will automatically minimize its
duty cycle to the minimum value but the output voltage is
still possible to be very high because there is no passive
component in the circuit try to absorb the energy. As a result,
Vout
(b) Buck-boost
Figure 3. Output Voltage Couples to C1 with a
Charging Current
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output voltage will rise up dramatically and burn the output
capacitor eventually. Hence, a zener diode Z1 or minimum
“dummy” load resistor is needed to consume the minimum
amount of energy as shown in Figure 1. It is also noted that
when R1 pulls up the output voltage at a given output current
condition, the output voltages at lower output current
conditions are also pulled up. Hence, the clamping zener
diode Z1 is needed to be with the breakdown voltage as same
as the output voltage but it will reduce some of the efficiency
at lower output current conditions.
Because of burst-mode control, the effective maximum
duty is lower and said to be 70% roughly. When a buck
converter is in continuous conduction mode (CCM), the
input voltage Vin and output voltage Vout are related by the
duty ratio D.
DESIGN CONSIDERATION
Another aspect on topology is the output current. The
maximum output current is always smaller than the
maximum switch current in non-isolated topologies.
However, in isolated topologies such as flyback the
maximum output current can be increased by a transformer.
Vout
D 0.7
Vin
(eq. 2)
The relationship in buck-boost is
Vout
D 0.7 2.33
1 0.7
Vin
1D
Topology
Buck circuit is to step down a voltage. Buck-boost circuit
is to step up or down a voltage. The output voltage is
inverted. The maximum duty of NCP1052 is typically 77%.
(eq. 3)
Table 1. Summary of Topology Difference Using NCP1052
Buck
Buck-boost
Flyback
Output voltage
< 0.7 Vin
Negative & < 2.33 Vin
Depending on transformer ratio
Output current
< 300 mA
<< 300 mA, output current is
only a portion of the inductor
current
< 10 W. It depends on operating
condition and audible noise level
Input voltage
< 700 V
<< 700 V. It depends on
transformer ratio
Operating mode in nominal
condition
Continuous
700 Vout V
700 V
Continuous
Standby ability on VCC charging
current
Bad. The current flows through
output even if there is no load
Good. The current passes
through inductor only
Good. The current passes
through primary winding only
Transformer / Auxiliary winding
It is only for standby
improvement or additional
output
It is only for standby
improvement or additional
output
It is a must for the main output.
Additional auxiliary winding can
improve standby performance
Isolation
No
No
Yes. Opto coupler can be
eliminated if isolation is not
needed
Discontinuous
Burst-mode Operation
The NCP1052 is with a burst-mode control method. It
means the MOSFET can be completely off for one or more
switching cycles. The output voltage is regulated by the
overall duration of dead time or non-dead time over a
number of switching cycles. This feature offers advantages
on saving energy in standby condition since it can reduce the
effective duty cycle dramatically. In flyback topology, the
circuit is mainly designed for discontinuous conduction
mode (DCM) in which the inductor current reaches zero in
every switching cycle. The DCM burst-mode waveform can
be represented in Figure 4. It is similar to the pulse-width
modulation (PWM) one.
Burst mode
PWM
Figure 4. DCM Inductor Currents in Burst Mode
and PWM Control
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In non-isolated topologies such as buck or buck-boost,
the circuits are mainly designed for CCM. The CCM
burst-mode waveform is different to the PWM waveform in
Figure 5. Because of this characteristic, burst mode requires
a higher peak value of the inductor current in order to have
the same level of averaged inductor current (or output
current).
Vout
VCC
FB current
time
Output waveforms with big enough VCC capacitor
Burst mode
Desired level of Vout
VCC
PWM
Vout
Figure 5. CCM Inductor Currents in Burst Mode
and traditional PWM Control
time
Output waveforms with too small VCC capacitor
As shown in Figure 4 and 5 burst-mode control produces
low-frequency waveform comparing to the switching
frequency. Part of the power loss in this low frequency
becomes audible noise. Therefore, burst-mode control is
not suitable for high power applications such as more than
20 W.
Figure 6. Startup Scenarios of the Circuits with
Big Enough or Too Small VCC Capacitor
Practically, the NCP1052 consumes approximately 0.5
mA in normal operation. The concerned fault sampling time
for feedback signal is from 8.5 V to 7.5V. Hence,
VCC Capacitor
-3
C I dt 0.5 10
· sampling time
1
dV
0.5 10- 3 · sampling time
The VCC capacitor C2 is the key component to make the
circuit operate in normal mode or fault mode. The device
recognizes a fault condition when there is no feedback
current in the FB pin during the time from VCC = 8.5 V to
7.5 V. The VCC capacitor directly affects this time duration.
In normal mode, the VCC follows a 8.5 V-7.5 V-8.5 V
hysteresis loop. When the circuit is in fault mode, the VCC
follows a 8.5 V-7.5 V-4.5 V-8.5 V hysteresis loop. The
device keeps its MOSFET opened except for the time from
VCC = 8.5 V to 7.5 V and delivers a little amount of power
to the output in fault mode.
A common and extreme case to enter fault condition is the
startup. The MOSFET begins switching at the VCC is firstly
charged to 8.5 V and hence output voltage rises. The output
voltage needs some time to build up the output voltage from
0 V to a desired value. When the desired level is reached, a
feedback current flows into the device to stop its switching.
If the feedback current is determined before VCC reaches
7.5V, the circuit will remain in normal mode. Otherwise, the
circuit will enter the fault mode and cannot provide the
output voltage at its desired level. Therefore, the VCC
capacitor is needed to be big enough to ensure sufficient time
for VCC going from 8.5 V to 7.5 V to sample feedback
current in startup.
(eq. 4)
For example, if sampling time or startup transient is
designed to be 20 ms, 10 µF VCC capacitor is needed.
Inductor
The 300 mA current limit in the NCP1052 is measured
with a condition that the di/dt reaches 300 mA in 4 µs. When
the buck or buck-boost circuit is designed for universal ac
input voltage (85 to 265 Vac), the rectified input voltage will
be possibly as high as 375 Vdc. In order to keep the 4 µs
condition, the inductance value will be 5 mH by (5) and (6).
For buck,
di Vin Vout Vin
dt
L
L
(eq. 5)
For buck-boost,
di Vin
dt
L
(eq. 6)
The 5 mH is practically too high and hence not very
practical. Therefore, the inductor is basically selected by
market available inductor models which is with a normally
smaller inductance (but not too small). It must have enough
saturation current level (>300 mA). If inductance is too
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AND8098/D
Buffering Capacitor
small, the di/dt becomes too high and the NCP1052 will
have a very high current limit effectively because there is a
propagation delay (typically 135 ns) to turn off the switch.
The current flowing through the inductor L includes three
parts. First, there is a VCC charging current Istart in Figure 2.
It happens when VCC needs charging. Its magnitude is 6.3
mA. It is noted that the VCC discharging current does not
flow through the inductor. Second, it is the main inductor
current to deliver the output current. It is noted that the peak
of burst-mode inductor current is higher than PWM one as
in Figure 5 for the same level of averaged inductor current
(or output current). Finally, there is a current flowing
through diode D1 to charge up C1. It also flows through the
inductor as shown in Figure 3. Its magnitude is a
greater-than-50 µA current and practically it is about 1 mA.
Hence, the saturation current of the inductor L is needed to
be bigger than their sum.
Another consideration on the inductor is the low-pass
filtering capability for the VCC hysteresis low frequency
(and the 50/ 60 Hz rectified AC line voltage ripple). As
shown in Figure 2, there is a low-frequency charging current
with magnitude 6.3 mA flowing through the inductor and
causes low-frequency ripple in the output voltage. A higher
value of the inductance can help to reduce the output ripple.
It is noted that when the output power is higher, the startup
time becomes longer. It needs bigger VCC capacitor and
makes lower VCC charging frequency. As a result, a bigger
inductance is needed.
The last consideration is the effect of load regulation.
Large inductor can limit the inrush current flowing into
capacitor C1 as shown in Figure 3. High inrush current is not
desirable because it can make the C1 voltage higher than the
output voltage. It makes load regulation poor. If there is no
pull-up resistor R1, inductor value L is chosen to be as large
as possible, say 2 mH.
Buffering capacitor C2 is to provide a greater-than-50 µA
to the feedback pin of NCP1052. It is relatively much
smaller than the output capacitor because the current
consumption in this capacitor is much smaller and the output
voltage cannot copy to this buffering capacitor if the
buffering capacitor voltage is higher than the output voltage.
Diodes
D and D1 are recommended to be the same part for
compatibility in speed and voltage drop. It helps the voltage
in the capacitor C1 to be similar to the output voltage. The
reverse blocking voltage of D and D1 is needed to be large
enough to withstand the input voltage in buck and input
voltage plus output voltage in buck-boost respectively.
D2 is not a critical component. Its function is to make sure
that feedback current is only in one direction. The accuracy
of its voltage drop used in (1) is not important since the 4.3V
reference voltage in the NCP1052 is loosely set.
Zener Diodes
Z1 is to clamp the output voltage when there is light load
or no load. Hence, the accuracy of Z1 helps the regulation
accuracy in the light load or no load condition. It is also the
main component to consume energy when the circuit is in no
load condition. The output voltage is clamped and hence the
output capacitor is protected.
Z2 and R1 are to set the output voltage at the nominal load
current. Hence, their accuracy affects the regulation
accuracy at the nominal load condition. The relationship
between zener voltage and output voltage is shown in (1).
Higher value of R1 helps to pull up the output voltage higher
by reducing the charging rate of the buffering capacitor C1.
Standby Condition
The standby ability of the proposed buck converter is not
good. It is because there is a VCC charging current Istart flows
through the output capacitor in Figure 2(a). This charging
current is a low-frequency pulsating signal. As a result, the
voltage in the output capacitor continuously rises up by the
charging current pulses. In order to prevent over voltage in
the output capacitor, the zener Z1 absorbs the charging
current. It consumes main portion of energy in standby.
Output Capacitor
Because of the burst-mode characteristic and the
low-frequency VCC charging current, the output ripple is
larger than those in PWM. Hence, a relatively bigger output
capacitor is needed to keep output ripple small. However,
big output capacitor needs a long time to build up the output
voltage initially and hence the circuit may enter into fault
mode in the startup in Figure 6.
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AND8098/D
The proposed buck-boost is better in term of the standby
ability. It is because the VCC charging current in Figure 2(b)
only passes through the inductor. The charging current
pulses become an averaged energy stored in the inductor and
consume smaller amount of power comparing to the buck
case.
fault mode with the 4.5 V-8.5 V-7.5 V-4.5 V hysteresis
loop.
Another method to supply the VCC voltage is coupling
capacitor technique in Figure 8. The output voltage is
coupled to the inserted capacitor when the diodes are closed.
The voltage drop of the diodes compensate each other.
Hence, the diode voltage drop effect can be neglected. The
NCP1052 needs a nominal VCC voltage of 8V. The inserted
resistor consumes some voltage from the output voltage Vout
to make a 8V to the VCC pin. Based on the 0.5mA typical
current consumption of VCC pin. The inserted resistance
value is (Vout - 8) / 0.5 k.
(a) Buck
(a) Buck
(b) Buck-boost
Figure 7. Auxiliary Winding to improve standby
Abillity
(b) Buck-boost
The auxiliary winding to supply the VCC voltage in Figure
7 is a method to improve the standby ability. The auxiliary
winding keeps the VCC voltage above 7.5 V and disable the
VCC charging current and hence its standby loss. The
auxiliary winding is coupled from the inductor L with
polarity same as the regulated output voltage. The VCC
voltage in the auxiliary winding is designed to be between
the normal VCC limits of 7.5 and 8.5 V typically. The
frequency jittering feature loses when the VCC voltage is
fixed. When output is shorted, there will be no voltage
coming from the auxiliary winding and the circuit will enter
Figure 8. Coupling Capacitor Technique to
Improve Standby Abillity
Temperature Rise
The NCP1052 is a very compact package with the control
circuit and high-voltage power switch. Its typical on
resistance is 22 Ω. Temperature rise exists. It is
recommended to design the PCB board with a large copper
area next to the device as a heatsink. This heatsink decreases
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the temperature rise and reduces the on resistance. Finally,
the efficiency of the circuit is benefited.
As shown in Figure 9, a 2 inch by 1.5 inch small
surface-mount demo board of 12 V / 100 mA buck is
presented. The design is made on a single-sided board. The
bill of material is shown in Table 2. The component symbols
are those in Figure 1. In order to have sufficient startup
ability, the VCC capacitor is 6.8 µF which gives a 3.4 ms fault
sampling time. Because of this feature, the circuit enters
fault mode when output current exceeds 200mA after startup
as shown in Figure 10(b). The efficiency of the circuit is
typically 65% at 100 mA.
EXAMPLES
12 V / 100 mA NCP1052 Buck Demo Board
Figure 9. Layout of the Demo Board
Table 2. Bill of Material of Buck Demo Board
Part No
Description
Manufacturer
IC
NCP1052ST136
Switching Regulator
ON Semiconductor
D, D1
MURS160T3
1A 600V ultrafast
ON Semiconductor
D2
MMSD914T1
General diode
ON Semiconductor
D3
MRA4005T1
1A 600V standard recovery
ON Semiconductor
Z1
MMSZ12T1
12V 5% zener
ON Semiconductor
Z2
MMSZ6V8T1
6.8V 5% zener
ON Semiconductor
R1
CRCW08052001FRT1
2 kΩ
Vishay
C
594D227X9016R2T
220 µF, 16 V, tantalum
Vishay
C1
VJ1206Y224KXXAT
0.22 µF, 25 V, ceramic
Vishay
C2
595D685X9016A2T
6.8µF, 16V, tantalum
Vishay
C3
400WA10M12.5X16
400V 10µF
Rubycon
L
UP2B-681
680µH
Cooper
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OUTPUT VOLTAGE (V)
AND8098/D
14
Dual Output Buck-boost with Increased Output
Current Capability
12
Replacing NCP1052 by NCP1055, which is with a current
limit of 680 mA, the output current capability is increased.
Larger value of inductor L is selected for high current. On
the other hand, the current consumption of NCP1055 is
higher than NCP1052 and the startup transient time is longer
in a higher power application. Hence, the VCC capacitor is
increased. When the VCC capacitor increased, its charging
frequency is decreased. Output capacitor is also needed to be
increased to reduce this lower-frequency charging current/
ripple.
In addition, by adding one more auxiliary winding to the
inductor a secondary output is made. A typical example is
shown in Figure 11. In higher output current application, the
load regulation is the major problem. The 5.1kΩ resistor
plays an important role for the load regulation. The primary
output voltage is higher than the secondary because it can
increase the output current ability by stepping up the current
in the transformer. The line regulation is shown in Figure 12
when the output currents are constant.
10
8
6
VIN = 300 Vdc
VIN = 100 Vdc
4
2
VIN = 200 Vdc
0
0
50
100
200
150
250
300
350
OUTPUT CURRENT (mA)
(a) Load Regulation
80
70
VIN = 100 Vdc
EFFICIENCY (%)
60
VIN = 200 Vdc
50
VIN = 300 Vdc
40
30
20
10
0
0
50
100
150
200
250
300
OUTPUT CURRENT (mA)
(b) Efficiency
Figure 10. 12V / 100mA Buck Performance
1N4005 1N4746
MUR160
5.1k
1µF
NCP1055P100
MUR160
1N4005
-24V / 200mA
22µF
Universal
AC Input
10µF
150µF
GND
1.2mH / 92.3µH
220µF
MUR160
Figure 11. Dual Output Buck-boost
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-5V / 150mA
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0
CONCLUSION
100 mA high-voltage low-cost buck and buck-boost
circuits using NCP1052 are presented. These circuits are
designed for cost-saving non-isolated application so that
optocoupler and transformer are saved. The possible input
voltage range is from 20 Vdc to 700 Vdc so that it is suitable
for general AC/DC and DC/DC applications with positive or
negative output voltages. It is noted that the standby ability
of the circuits is not good because of the VCC capacitor
charging current. However, it can be improved by adding an
auxiliary winding to the VCC. The design consideration of
each component in the circuits is explained. By replacing the
NCP1052 with NCP1055, the output current can be
increased. By adding an auxiliary winding, multi-output can
be obtained. A 12 V / 100 mA demo board is presented with
typical 65% efficiency.
OUTPUT VOLTAGE (V)
Output 2 with 150 mA
-5
-10
-15
-20
Output 1 with 200 mA
-25
50
100
150
200
250
300
INPUT VOLTAGE (Vac)
Figure 12. Line Regulation of the Dual Output
Buck-boost
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