30-F2127PA100SC-L179E09 Output Inverter Application flow 7PACK 2 1200 V / 100 A General conditions 3phase SPWM V GEon = 15 V V GEoff = -15 V R gon = 4 Ω R goff = 4 Ω Figure 1 IGBT Figure 2 Typical average static loss as a function of output current P loss = f(I out) FWD Typical average static loss as a function of output current P loss = f(I out) Ploss (W) 160 Ploss (W) 250 Mi*cosfi = 1 200 Mi*cosf i= -1 140 120 100 150 80 100 60 40 50 20 Mi*cosfi = -1 Mi*cosfi = 1 0 0 20 40 60 80 100 120 140 0 160 0 20 40 60 80 100 120 Iout (A) At Tj = 150 At Tj = °C 150 °C Mi*cosφ from -1 to 1 in steps of 0,2 Figure 3 IGBT Typical average switching loss as a function of output current Figure 4 P loss = f(I out) 180,0 fsw = 16kHz 160,0 FWD Typical average switching loss as a function of output current Ploss (W) Ploss (W) 160 Iout (A) Mi*cosφ from -1 to 1 in steps of 0,2 P loss = f(I out) 90,0 fsw = 16kHz 80,0 140,0 70,0 120,0 60,0 100,0 50,0 80,0 40,0 60,0 30,0 40,0 20,0 10,0 20,0 fsw = 2kHz fsw = 2kHz 0,0 0,0 0 20 40 60 80 100 120 140 0 160 20 40 60 80 100 120 Iout (A) At Tj = 140 150 160 Iout (A) At Tj = °C DC link = 600 V f sw from 2 kHz to 16 kHz in steps of factor 2 copyright Vincotech 140 150 °C DC link = 600 V f sw from 2 kHz to 16 kHz in steps of factor 2 1 27 Jul. 2015 / Revision 1 30-F2127PA100SC-L179E09 Output Inverter Application flow 7PACK 2 Figure 5 Phase Figure 6 Typical available 50Hz output current as a function Mi*cosφ I out = f(Mi*cos φ ) Phase Typical available 50Hz output current as a function of switching frequency I out = f(f sw) Iout (A) 160 Iout (A) 1200 V / 100 A Th = 60°C 140 160 140 Th = 60°C 120 120 Th = 100°C 100 100 80 80 Th = 100°C 60 60 40 40 20 20 0 -1,0 -0,8 -0,6 -0,4 -0,2 0,0 0,2 0,4 0,6 0,8 0 1,0 1 10 100 Mi*cos φ At Tj = 150 fsw (kHz) At Tj = °C DC link = 600 V f sw = 4 kHz T h from 60 °C to 100 °C in steps of 5 °C 150 °C DC link = 600 V Mi*cos φ =0,8 T h from 60 °C to 100 °C in steps of 5 °C Figure 7 Phase Figure 8 Typical available 50Hz output current as a function of Mi*cos φ and switching frequency I out = f(f sw, Mi*cos φ ) Iout (Apeak) -1,00 -0,80 Iout (A) -0,60 130,0-150,0 -0,40 110,0-130,0 -0,20 Phase Typical available 0Hz output current as a function of switching frequency I outpeak = f(f sw) 160 140 120 Mi*cosfi 0,00 90,0-110,0 100 Th = 60°C 80 0,20 60 70,0-90,0 0,40 40 50,0-70,0 0,60 30,0-50,0 20 0,80 Th = 100°C 0 1,00 1 2 4 8 16 32 64 1 10 100 fsw At Tj = fsw (kHz) 150 °C At Tj = DC link = 600 Th = 80 V °C DC link = 600 V T h from 60 °C to 100 °C in steps of 5 °C Mi = copyright Vincotech 2 150 °C 0 27 Jul. 2015 / Revision 1 30-F2127PA100SC-L179E09 Output Inverter Application flow 7PACK 2 Figure 9 Inverter Figure 10 Inverter Typical efficiency as a function of output power efficiency=f(Pout) efficiency (%) Pout (kW) Typical available peak output power as a function of heatsink temperature P out=f(T h) 70,0 1200 V / 100 A 2kHz 60,0 100,0 99,0 2kHz 98,0 50,0 97,0 96,0 40,0 16kHz 16kHz 95,0 30,0 94,0 93,0 20,0 92,0 10,0 91,0 0,0 50 55 60 65 70 75 80 85 90 95 90,0 100 0,0 10,0 20,0 30,0 40,0 50,0 60,0 Th (oC) At Tj = 150 DC link = Mi = cos φ= f sw from 600 V 1 0,80 2 kHz to 16 kHz in steps of factor 2 80,0 90,0 Pout (kW) °C Figure 11 70,0 At Tj = 150 DC link = Mi = cos φ= f sw from 600 V 1 0,80 2 kHz to 16 kHz in steps of factor 2 °C Inverter Overload (%) Typical available overload factor as a function of motor power and switching frequency P peak / P nom=f(P nom,fsw) 400 350 300 250 200 150 Switching frequency (kHz) 100 Motor/ 14,71 nominal25,00 power (HP/kW) 20,00 / 18,39 30,00 / 22,07 40,00 / 29,42 50,00 / 36,78 60,00 / 44,13 1 374 300 250 187 150 125 2 374 300 250 187 150 125 4 374 300 250 187 150 125 8 361 288 240 180 144 120 16 289 232 193 145 116 0 At Tj = 150 DC link = Mi = cos φ= f sw from Th = 600 V 1 0,8 1 kHz to 16kHz in steps of factor 2 80 °C °C Motor eff =0,85 copyright Vincotech 3 27 Jul. 2015 / Revision 1