30 F2127PA100SC L179E09 D1 19

30-F2127PA100SC-L179E09
Output Inverter Application
flow 7PACK 2
1200 V / 100 A
General conditions
3phase SPWM
V GEon = 15 V
V GEoff = -15 V
R gon = 4 Ω
R goff = 4 Ω
Figure 1
IGBT
Figure 2
Typical average static loss as a function of output
current
P loss = f(I out)
FWD
Typical average static loss as a function of output
current
P loss = f(I out)
Ploss (W)
160
Ploss (W)
250
Mi*cosfi = 1
200
Mi*cosf i= -1
140
120
100
150
80
100
60
40
50
20
Mi*cosfi = -1
Mi*cosfi = 1
0
0
20
40
60
80
100
120
140
0
160
0
20
40
60
80
100
120
Iout (A)
At
Tj =
150
At
Tj =
°C
150
°C
Mi*cosφ from -1 to 1 in steps of 0,2
Figure 3
IGBT
Typical average switching loss
as a function of output current
Figure 4
P loss = f(I out)
180,0
fsw = 16kHz
160,0
FWD
Typical average switching loss
as a function of output current
Ploss (W)
Ploss (W)
160
Iout (A)
Mi*cosφ from -1 to 1 in steps of 0,2
P loss = f(I out)
90,0
fsw = 16kHz
80,0
140,0
70,0
120,0
60,0
100,0
50,0
80,0
40,0
60,0
30,0
40,0
20,0
10,0
20,0
fsw = 2kHz
fsw = 2kHz
0,0
0,0
0
20
40
60
80
100
120
140
0
160
20
40
60
80
100
120
Iout (A)
At
Tj =
140
150
160
Iout (A)
At
Tj =
°C
DC link = 600
V
f sw from
2 kHz to 16 kHz in steps of factor 2
copyright Vincotech
140
150
°C
DC link = 600
V
f sw from
2 kHz to 16 kHz in steps of factor 2
1
27 Jul. 2015 / Revision 1
30-F2127PA100SC-L179E09
Output Inverter Application
flow 7PACK 2
Figure 5
Phase
Figure 6
Typical available 50Hz output current
as a function Mi*cosφ
I out = f(Mi*cos φ )
Phase
Typical available 50Hz output current
as a function of switching frequency I out = f(f sw)
Iout (A)
160
Iout (A)
1200 V / 100 A
Th = 60°C
140
160
140
Th = 60°C
120
120
Th = 100°C
100
100
80
80
Th = 100°C
60
60
40
40
20
20
0
-1,0
-0,8
-0,6
-0,4
-0,2
0,0
0,2
0,4
0,6
0,8
0
1,0
1
10
100
Mi*cos φ
At
Tj =
150
fsw (kHz)
At
Tj =
°C
DC link = 600
V
f sw =
4
kHz
T h from
60 °C to 100 °C in steps of 5 °C
150
°C
DC link = 600
V
Mi*cos φ =0,8
T h from
60 °C to 100 °C in steps of 5 °C
Figure 7
Phase
Figure 8
Typical available 50Hz output current as a function of
Mi*cos φ and switching frequency
I out = f(f sw, Mi*cos φ )
Iout (Apeak)
-1,00
-0,80
Iout (A)
-0,60
130,0-150,0
-0,40
110,0-130,0
-0,20
Phase
Typical available 0Hz output current as a function
of switching frequency
I outpeak = f(f sw)
160
140
120
Mi*cosfi
0,00
90,0-110,0
100
Th = 60°C
80
0,20
60
70,0-90,0
0,40
40
50,0-70,0
0,60
30,0-50,0
20
0,80
Th = 100°C
0
1,00
1
2
4
8
16
32
64
1
10
100
fsw
At
Tj =
fsw (kHz)
150
°C
At
Tj =
DC link = 600
Th =
80
V
°C
DC link = 600
V
T h from
60 °C to 100 °C in steps of 5 °C
Mi =
copyright Vincotech
2
150
°C
0
27 Jul. 2015 / Revision 1
30-F2127PA100SC-L179E09
Output Inverter Application
flow 7PACK 2
Figure 9
Inverter
Figure 10
Inverter
Typical efficiency as a function of output power
efficiency=f(Pout)
efficiency (%)
Pout (kW)
Typical available peak output power as a function of
heatsink temperature
P out=f(T h)
70,0
1200 V / 100 A
2kHz
60,0
100,0
99,0
2kHz
98,0
50,0
97,0
96,0
40,0
16kHz
16kHz
95,0
30,0
94,0
93,0
20,0
92,0
10,0
91,0
0,0
50
55
60
65
70
75
80
85
90
95
90,0
100
0,0
10,0
20,0
30,0
40,0
50,0
60,0
Th (oC)
At
Tj =
150
DC link =
Mi =
cos φ=
f sw from
600
V
1
0,80
2 kHz to 16 kHz in steps of factor 2
80,0
90,0
Pout (kW)
°C
Figure 11
70,0
At
Tj =
150
DC link =
Mi =
cos φ=
f sw from
600
V
1
0,80
2 kHz to 16 kHz in steps of factor 2
°C
Inverter
Overload (%)
Typical available overload factor as a function of
motor power and switching frequency P peak / P nom=f(P nom,fsw)
400
350
300
250
200
150
Switching frequency (kHz)
100
Motor/ 14,71
nominal25,00
power
(HP/kW)
20,00
/ 18,39
30,00 / 22,07
40,00 / 29,42
50,00 / 36,78
60,00 / 44,13
1
374
300
250
187
150
125
2
374
300
250
187
150
125
4
374
300
250
187
150
125
8
361
288
240
180
144
120
16
289
232
193
145
116
0
At
Tj =
150
DC link =
Mi =
cos φ=
f sw from
Th =
600
V
1
0,8
1 kHz to 16kHz in steps of factor 2
80
°C
°C
Motor eff =0,85
copyright Vincotech
3
27 Jul. 2015 / Revision 1
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