10-FZ122PA050SC-P997F08 datasheet Output Inverter Application flow PHASE 0 1200 V / 50 A General conditions 3phase SPWM V GEon = 15 V V GEoff = -15 V R gon = 8 Ω R goff = 8 Ω Figure 1 IGBT Figure 2 FWD Typical average static loss as a function of output current Typical average static loss as a function of output current P loss = f(I out) P loss = f(I out) 80 Ploss (W) Ploss (W) 120 70 100 Mi*cosfi = 1 60 Mi*cosf i= -1 80 50 40 60 30 40 20 20 10 Mi*cosfi = 1 Mi*cosfi = -1 0 0 0 At Tj = 10 20 150 30 40 50 60 70 Iout (A) 0 80 At Tj = °C Mi*cosφ from -1 to 1 in steps of 0,2 20 150 30 40 50 60 70 Iout (A) 80 °C Mi*cosφ from -1 to 1 in steps of 0,2 Figure 3 IGBT Typical average switching loss as a function of output current Figure 4 FWD Typical average switching loss as a function of output current P loss = f(I out) Ploss (W) Ploss (W) 10 100,0 90,0 P loss = f(I out) 40,0 35,0 80,0 fsw = 16kHz fsw = 16kHz 30,0 70,0 25,0 60,0 20,0 50,0 40,0 15,0 30,0 10,0 20,0 5,0 10,0 fsw = 2kHz fsw = 2kHz 0,0 0,0 0 At Tj = 10 150 20 30 40 50 60 70Iout (A) 0 80 At Tj = °C DC-link = 600 V f sw from 2 kHz to 16 kHz in steps of factor 2 copyright Vincotech 10 150 20 30 40 50 60 70 80 Iout (A) °C DC-link = 600 V f sw from 2 kHz to 16 kHz in steps of factor 2 1 12 Jan. 2016 / Revision 2 10-FZ122PA050SC-P997F08 datasheet Output Inverter Application flow PHASE 0 Figure 5 Phase Figure 6 Typical available 50Hz output current as a function Mi*cosφ I out = f(Mi*cos φ ) Phase Typical available 50Hz output current as a function of switching frequency I out = f(f sw) Iout (A) 80 Iout (A) 1200 V / 50 A Th = 60°C 80 70 70 60 60 Th = 60°C Th = 100°C Th = 100°C 50 50 40 40 30 30 20 20 10 10 0 -1,0 At Tj = 0 -0,8 -0,6 -0,4 150 -0,2 0,0 0,2 0,4 0,6 0,8 1,0 Mi*cos φ 1 At Tj = °C DC-link = 600 V f sw = 4 kHz T h from 60 °C to 100 °C in steps of 5 °C 10 150 fsw (kHz) 100 °C DC-link = 600 V Mi*cos φ =0,8 T h from 60 °C to 100 °C in steps of 5 °C Figure 7 Phase Figure 8 Typical available 50Hz output current as a function of Mi*cos φ and switching frequency I out = f(f sw, Mi*cos φ ) Iout (Apeak) -1,00 -0,80 Iout (A) Phase Typical available 0Hz output current as a function of switching frequency I outpeak = f(f sw) 80 70 -0,60 60 -0,40 70,0-80,0 50 60,0-70,0 Th = 60°C 40,0-50,0 0,00 30,0-40,0 20,0-30,0 Mi*cosfi -0,20 50,0-60,0 40 0,20 Th = 100°C 30 10,0-20,0 0,40 20 0,60 10 0,80 0 1,00 1 2 4 8 16 32 64 1 fsw (kHz) At Tj = 10 fsw (kHz) 150 °C At Tj = DC-link = 600 Th = 80 V °C DC-link = 600 V T h from 60 °C to 100 °C in steps of 5 °C Mi = copyright Vincotech 2 150 100 °C 0 12 Jan. 2016 / Revision 2 10-FZ122PA050SC-P997F08 datasheet Output Inverter Application flow PHASE 0 Figure 9 Inverter Figure 10 Inverter Typical efficiency as a function of output power efficiency=f(Pout) efficiency (%) Typical available peak output power as a function of heatsink temperature P out=f(T h) Pout (kW) 1200 V / 50 A 35,0 2kHz 30,0 100,0 2kHz 99,0 98,0 25,0 97,0 16kHz 96,0 20,0 95,0 16kHz 15,0 94,0 93,0 10,0 92,0 5,0 91,0 0,0 90,0 60 65 At Tj = 70 150 80 85 90 95 100 Th ( o C) 0,0 At Tj = °C DC-link = 600 Mi = 1 cos φ= f sw from 75 V 5,0 150 DC-link = 600 Mi = 1 0,80 2 kHz to 16 kHz in steps of factor 2 cos φ= f sw from Figure 11 10,0 15,0 20,0 25,0 30,0 35,0 40,0 45,0 Pout (kW) °C V 0,80 2 kHz to 16 kHz in steps of factor 2 Inverter Overload (%) Typical available overload factor as a function of motor power and switching frequency P peak / P nom=f(P nom,fsw) 500 450 400 350 300 250 200 Switching frequency (kHz) 150 Motor nominal power (HP/kW) 100 7,50 / 5,52 10,00 / 7,36 15,00 / 11,03 20,00 / 14,71 25,00 / 18,39 30,00 / 22,07 1 499 374 250 187 150 125 2 499 374 250 187 150 125 4 499 374 249 187 150 125 8 439 329 219 164 132 0 16 343 258 172 129 0 0 At Tj = 150 DC-link = 600 °C V Mi = 1 cos φ= f sw from Th = 0,8 1 kHz to 16kHz in steps of factor 2 80 °C Motor eff =0,85 copyright Vincotech 3 12 Jan. 2016 / Revision 2