10 FZ122PA050SC P997F08 D2 19

10-FZ122PA050SC-P997F08
datasheet
Output Inverter Application
flow PHASE 0
1200 V / 50 A
General conditions
3phase SPWM
V GEon = 15 V
V GEoff = -15 V
R gon = 8 Ω
R goff = 8 Ω
Figure 1
IGBT
Figure 2
FWD
Typical average static loss as a function of output current
Typical average static loss as a function of output current
P loss = f(I out)
P loss = f(I out)
80
Ploss (W)
Ploss (W)
120
70
100
Mi*cosfi = 1
60
Mi*cosf i= -1
80
50
40
60
30
40
20
20
10
Mi*cosfi = 1
Mi*cosfi = -1
0
0
0
At
Tj =
10
20
150
30
40
50
60
70
Iout (A)
0
80
At
Tj =
°C
Mi*cosφ from -1 to 1 in steps of 0,2
20
150
30
40
50
60
70
Iout (A)
80
°C
Mi*cosφ from -1 to 1 in steps of 0,2
Figure 3
IGBT
Typical average switching loss
as a function of output current
Figure 4
FWD
Typical average switching loss
as a function of output current
P loss = f(I out)
Ploss (W)
Ploss (W)
10
100,0
90,0
P loss = f(I out)
40,0
35,0
80,0
fsw = 16kHz
fsw = 16kHz
30,0
70,0
25,0
60,0
20,0
50,0
40,0
15,0
30,0
10,0
20,0
5,0
10,0
fsw = 2kHz
fsw = 2kHz
0,0
0,0
0
At
Tj =
10
150
20
30
40
50
60
70Iout (A)
0
80
At
Tj =
°C
DC-link = 600
V
f sw from 2 kHz to 16 kHz in steps of factor 2
copyright Vincotech
10
150
20
30
40
50
60
70
80
Iout (A)
°C
DC-link = 600
V
f sw from 2 kHz to 16 kHz in steps of factor 2
1
12 Jan. 2016 / Revision 2
10-FZ122PA050SC-P997F08
datasheet
Output Inverter Application
flow PHASE 0
Figure 5
Phase
Figure 6
Typical available 50Hz output current
as a function Mi*cosφ
I out = f(Mi*cos φ )
Phase
Typical available 50Hz output current
as a function of switching frequency I out = f(f sw)
Iout (A)
80
Iout (A)
1200 V / 50 A
Th = 60°C
80
70
70
60
60
Th = 60°C
Th = 100°C
Th = 100°C
50
50
40
40
30
30
20
20
10
10
0
-1,0
At
Tj =
0
-0,8
-0,6
-0,4
150
-0,2
0,0
0,2
0,4
0,6
0,8
1,0
Mi*cos φ
1
At
Tj =
°C
DC-link = 600
V
f sw =
4
kHz
T h from
60 °C to 100 °C in steps of 5 °C
10
150
fsw (kHz)
100
°C
DC-link = 600
V
Mi*cos φ =0,8
T h from
60 °C to 100 °C in steps of 5 °C
Figure 7
Phase
Figure 8
Typical available 50Hz output current as a function of
Mi*cos φ and switching frequency
I out = f(f sw, Mi*cos φ )
Iout (Apeak)
-1,00
-0,80
Iout (A)
Phase
Typical available 0Hz output current as a function
of switching frequency
I outpeak = f(f sw)
80
70
-0,60
60
-0,40
70,0-80,0
50
60,0-70,0
Th = 60°C
40,0-50,0
0,00
30,0-40,0
20,0-30,0
Mi*cosfi
-0,20
50,0-60,0
40
0,20
Th = 100°C
30
10,0-20,0
0,40
20
0,60
10
0,80
0
1,00
1
2
4
8
16
32
64
1
fsw
(kHz)
At
Tj =
10
fsw (kHz)
150
°C
At
Tj =
DC-link = 600
Th =
80
V
°C
DC-link = 600
V
T h from
60 °C to 100 °C in steps of 5 °C
Mi =
copyright Vincotech
2
150
100
°C
0
12 Jan. 2016 / Revision 2
10-FZ122PA050SC-P997F08
datasheet
Output Inverter Application
flow PHASE 0
Figure 9
Inverter
Figure 10
Inverter
Typical efficiency as a function of output power
efficiency=f(Pout)
efficiency (%)
Typical available peak output power as a function of
heatsink temperature
P out=f(T h)
Pout (kW)
1200 V / 50 A
35,0
2kHz
30,0
100,0
2kHz
99,0
98,0
25,0
97,0
16kHz
96,0
20,0
95,0
16kHz
15,0
94,0
93,0
10,0
92,0
5,0
91,0
0,0
90,0
60
65
At
Tj =
70
150
80
85
90
95
100
Th ( o C)
0,0
At
Tj =
°C
DC-link = 600
Mi =
1
cos φ=
f sw from
75
V
5,0
150
DC-link = 600
Mi =
1
0,80
2 kHz to 16 kHz in steps of factor 2
cos φ=
f sw from
Figure 11
10,0
15,0
20,0
25,0
30,0
35,0
40,0
45,0
Pout (kW)
°C
V
0,80
2 kHz to 16 kHz in steps of factor 2
Inverter
Overload (%)
Typical available overload factor as a function of
motor power and switching frequency P peak / P nom=f(P nom,fsw)
500
450
400
350
300
250
200
Switching frequency (kHz)
150
Motor nominal power (HP/kW)
100
7,50 / 5,52
10,00 / 7,36
15,00 / 11,03
20,00 / 14,71
25,00 / 18,39
30,00 / 22,07
1
499
374
250
187
150
125
2
499
374
250
187
150
125
4
499
374
249
187
150
125
8
439
329
219
164
132
0
16
343
258
172
129
0
0
At
Tj =
150
DC-link = 600
°C
V
Mi =
1
cos φ=
f sw from
Th =
0,8
1 kHz to 16kHz in steps of factor 2
80
°C
Motor eff =0,85
copyright Vincotech
3
12 Jan. 2016 / Revision 2
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