AME5250 Evaluation Board User Guide

AME5250 Evaluation Board User Guide
1. General Descriptions
The AME5250 is 1A, synchronous step-down DC/DC converter with integrated a main switch and a
synchronous rectifier without the need for external Schottky diode. The PWM operation is able to vary the
duty ratio linearly from 0 up to 100%. This device, available in DFN-6D package, is ideal suited for single
Li-Ion battery powered applications or other portable applications that require small board space.
2. Features
● High Efficiency - Up to 95%
● Very Low 20µA Quiescent Current
● High efficiency in light load condition
● 2.5V to 5.5V Input Range
● Adjustable Output Voltages From 0.6V to Vin
● 1.0V, 1.2V, 1.5V, 1.6V, 1.8V, 2.5V and 3.3V Fixed/Adjustable Output Voltage
● 1A Output Current
● Low Dropout Operation: 100% Duty Cycle
● No Schottky Diode Required
● 1.5MHz Constant Frequency PWM Operation
● Small DFN-6D Package
3. Applications
● Cellular Telephones
● MP3 Players
● Personal Information Appliances
● Portable Instruments
● Wireless and DSL Modems
Rev. A/01-2010
4. Evaluation Board Schematic
(4.1) AME5250 Typical Schematic
Figure 1.
(4.2) AME5250 Typical Schematic for 1.8V Output Voltage Application
Vin
5V
IN
U1
SW
2.2uH
REN
100K
EN
Cin
4.7uF
EN
Switch
Vout
1.8V/1A
L1
FB
AME5250-AVYADJ
C1
22pF
R1
150K
Cout
10uF
R2
75K
Figure 2.
Rev. A/01-2010
5. Bill of Materials
BOM for item (4.2)
Location
Q’ty
Value
Description
Part No.
Manufacture
Package
Cin
1
4.7µF/6.3V
Ceramic Capacitor
CL31A106MQHNNNE
Samsung
1206
Cout
1
10µF/6.3V
Ceramic Capacitor
CL31A106MQHNNNE
Samsung
1206
C1
1
22pF/50V
Ceramic Capacitor
CL10C220JB8NNNC
Samsung
0603
REN
1
100KΩ
Chip Resistor
CR-05FL7-100K
Viking
0805
R1
1
150KΩ
Chip Resistor
CR-05FL7-150K
Viking
0805
R2
1
75KΩ
Chip Resistor
CR-05FL7-75K
Viking
0805
L1
2
2.2uH
Inductor
CDRH5D16NP-2R2NC
Sumida
-
U1
1
-
AME5250-AVYADJ
AME
DFN-6D
PCB
1
-
Blank PCB
TM091201 Rev.A
AME
-
4
-
Copper Pillar
-
-
-
EN
1
-
Switch
TS-006S-5-190g
HSUAN YI
-
-
5
-
Test Pin
JT-1P-CIR
PINGOOD
-
-
4
-
Plastic Screw
S-306
PINGOOD
-
-
4
-
Spacer Support
H-6
PINGOOD
-
Vin, Vout,
POR, GND
1.5MHz, 1A Buck
Converter
6. Operating Instructions
(6.1) Connect Vin to the positive point of DC power supply and GND to supply ground.
(6.2) Connect Vout to the positive point of E-load and GND to supply ground or parallel an appropriate
resistor to pull up the loading.
(6.3) Importing a logic signal to EN pin will enable the AME5250. Logic high (VEN>1.5V) switches on
AME5250, logic low puts it into low current shutdown mode.
7. Application Information
(7.1) Setting Output Voltage
In the adjustable version, the regulated output voltage is set with an external resistor divider (R1 and
R2 in Figure 1.) from the output to the VFB pin and is determined by:
VOUT = VFB × (1 +
R1
)
R2
Where VFB = 0.6V for AME5250.
Rev. A/01-2010
(7.2) Capacitor Selection
(7.2.1) Input Capacitor Selection
The input capacitor should be chosen to handle the RMS ripple current of a buck converter.
The RMS current is calculated as the following equation:
I RMS = I OUT ( MAX ) ×
VOUT
VIN
×
−1
VIN
VOUT
Select the voltage rating should be 1.25 to 1.5 times greater than the maximum input voltage.
Multi-layer ceramic capacitors, which have very low ESR and can easily handle high RMS ripple
current. 4.7µF to 10µF ceramic capacitor is adequate for most applications. X5R and X7R types
are suitable because of their wider voltage and temperature ranges. To ensure stable operation,
Cin should be placed as close to the IC as possible.
(7.2.2) Output Capacitor Selection
The output ripple voltage ∆Vout of a buck converter is calculated as the following equations:
∆VOUT = ∆I L × ( ESRCOUT +
1
)
8 × f SW × COUT
Where:
∆Vout is the output ripple voltage.
∆IL is the output ripple current.
fsw is the switching frequency.
Cout is the output capacitance.
ESRout is the Equivalent Series Resistance of the output capacitor.
A 10µF ceramic capacitor is found adequate for output filtering in this application.
Rev. A/01-2010
(7.3) Inductor Value Calculation
The inductor ripple current for a synchronous step-down converter is calculated by using the following
equation:
∆I L =
VIN − VOUT VOUT
×
L × f SW
VIN
Where:
∆IL is the inductor ripple current.
fsw is the switching frequency.
L1 is the inductance.
For most applications, the value of the inductor will fall in the range of 1µH to 4.7µH.
(7.4) Board Layout Considerations
High frequency switching regulators require very careful layout of components in order to get stable
operation and low noise. A good PCB layout could make AME5250 working perfect to achieve the
best performance.
(7.5) PCB Layout Example
The PCB layout example is for standard step-down converter application with AME5250 device. It
proves this evaluation board can achieve reliable performance. It follows the layout guidelines below.
(7.5.1)
Keep the power traces, consisting of the GND trace, the SW trace and the Vin trace short
and wide.
(7.5.2) The inductor and SW pin should be kept extremely short.
(7.5.3) The input capacitor should be placed close to the IC’s Vin and GND pin.
(7.5.4) The feedback components R1, R2 and C1 must be kept close to the IC’s FB pin to prevent
noise injection on the FB pin trace and keeping far away from SW node. Connect
feedback trace behind the output capacitors.
Rev. A/01-2010
Figure 3. AME5250 Evaluation Board PCB Layout
Rev. A/01-2010