AN6550 Dual Operational Amplifier ■ Overview Unit:mm The AN6550 is a dual operational amplifier with a phase compensation circuit built-in, allowing low voltage operation. It is suitable for application to various electronic circuits such as active filters and audio preamplifiers. 2.4±0.25 3.3±0.25 6.0±0.3 2.54 9 6 23.3±0.3 5 4 2 1 + 0.1 0.3 – 0.05 3.0±0.3 ■ Pin Descriptions Pin No. 1.5±0.25 3 • Phase compensation circuit • High voltage gain, low noise • Output short protection circuit • Low voltage operation(±2.5V to±10V) 1.4±0.3 30˚ ■ Features 0.5±0.1 7 1.5±0.25 8 9-pin SIL Plastic Package (SIP009-P-0000C) Pin name 1 Ch.1 output 2 External bias 3 Ch.1 inverting input 4 Ch.1 non inverting input 5 VEE (GND) 6 Ch.2 non inverting input 7 Ch.2 inveting input 8 Ch.2 output 9 VCC ■ Block Diagram VCC 9 R3 R16 Q3 Vin1– Q1 3 R10 Q2 Q8 Vin1+ Q25 Q10 4 Q13 Q28 Q18 Q11 Q26 R6 R19 R22 Q17 Q14 Q29 Q21 R8 Q5 C1 R18 Q27 Q20 Q7 R1 R20 R13 Q7 Q6 Q4 R12 R7 R5 C4 Q24 Q9 C2 R2 Q16 R11 R9 R17 R4 1 5 2 8 VO1 VEE VEXT VO2 (GND) Q19 Q22 R21 7 Vin2– 6 Vin2+ Q23 R15 C3 R14 ■ Absolute Maximum Ratings (Ta=25˚C) Parameter Symbol Rating VCC, VEE ±12 V External bias supply voltage VEXT VEE to VCC V Differential input voltage VID ±24 V Common-mode input voltage VICM ±12 V PD 500 mW Supply voltage Voltage Power dissipation Temperature Unit Operating ambient temperature Topr –20 to +75 ˚C Storage temperature Tstg –55 to +150 ˚C ■ Electrical Characteristics (VCC=2.5V, VEE=–2.5V, VEXT=2.0V, Ta=25˚C) Parameter Symbol Input offset voltage VI (offset) Condition min RS < = 10kΩ typ max Unit 1.5 6 mV Input offset current IIO 5 200 nA Input bias current IBias 150 500 nA Voltage gain GV Maximum output voltage VO (max.) RL > = 2kΩ RL > = 10kΩ 65 100 dB ±1.2 ±1.7 V V ±1 ±1.5 Common-mode input voltage width VCM ±1 ±1.5 V Common-mode rejection ratio CMR 70 80 dB Supply voltage rejection ratio SVR RL > = 2kΩ 100 300 8 15 µV/V Power consumption PC Slew rate SR RL=∞ RL > = 2kΩ 0.8 V/µs Equivalent input noise voltage Vni RS=1kΩ, B=10Hz to 30kHz 2.5 µVrms ■ Pin Assignments 1 2 – + 3 4 5 + – 6 7 8 VO1 VEXT Vin1– Vin1+ VEE Vin2+ Vin2– VO2 9 VCC mW ■ Characteristics Curve GV–f VO (max.)–RL Voltage Gain GV (dB) Maximum Output VO (max.) (V) VCC=2.5V VEE=–2.5V VEXT=2V Ta=25˚C 100 80 60 40 20 0 1 VCC=2.5V VEE=–2.5V VEXT=2V Ta=25˚C 5 4 3 2 1 0 100 10 100 1k 10k 100k 1M 10M 100M Frequency f (Hz) 1k VO (max.)–VCC, VEE 5 0 –5 –10 –15 8 12 16 2 10 5 0 –5 –10 Maximum Output Voltage VO (max.) (V) Supply Current ICC (mA) 1 0 –1 –2 –3 16 20 0 –1 –2 –3 0 4 8 12 16 20 VCC=2.5V VEE=–2.5V VEXT=2V Ta=25˚C 1.0 0.8 0.6 9 VCC 3.7 0.4 – DUT + 4.6 5 VEXT 1.8 RL 2kΩ 2 VEE 0.2 0 10 20 30 40 50 Time t (µs) 60 70 –2 –1 0 1 2 External Bias Voltage VEXT (V) 0 12 Supply Voltage VCC=–VEE (V) 1 –15 VO–t 2 10k VCC=2.5V, VEE=–2.5V, Ta=25˚C Supply Voltage VCC=–VEE (V) VEXT–VEE=4.5V Ta=25˚C 1k ICC–VEXT 1.2 8 100 Frequency f (Hz) VEXT–VEE=4.5V, Ta=25˚C ICC–VCC, VEE 4 5 15 –20 20 4 0 10 3 Supply Voltage VCC=–VEE(V) 3 15 10 Supply Current ICC (mV) Commom Mode Input Voltage VCM (V) Maximum Output Voltage VO (max.) (V) 10 4 20 VCM–VCC, VEE VEXT–VEE=4.5V, Ta=25˚C 0 VCC=2.5V VEE=–2.5V VEXT=2V Ta=25˚C 100k 20 15 –4 10k 25 Load Resistance RL (Ω) 20 –20 Vni–f 6 Equivalent Input Noise Voltage Vni (nV/ Hz) 120 80 3 ■ Application Circuit 2200pF 36kΩ 0.01µF 390kΩ VCC=5—20V 100µF 9 100kΩ R1 10kΩ – 2.2kΩ 33µF 47µF + OP.OP. Amp. Amp. 2 5 VEXT R2 100kΩ 1kΩ 33pF 10kΩ 10kΩ RIAA Preamplifier (single power supply operation) Note) R1 and R2 are resistances for setting operational amplifier bias. Set R1 and R2 so that VEXT=2.0V to 6.0V. (Recommended Voltage VEXT=4.5V) ■ How to Apply External to the AN6550 1. The AN6550 is an operational amplifier with a phase compensation circuit built-in, allowing low voltage operation, and its current consumption and bandwidth can be changed by applying external bias to it. 2. As shown below, applys bias voltage to 2 VEXT pin of the AN6550 allows the AN6550 to be handled in the very same way as the AN6551, except for pin connection. 1 ) By diode VCC 9 R=1kΩ —10kΩ AN6550 2 VEXT 5 VEE Set VEXT > = VEE+1V. 2 ) By connecting VEXT pin to GND 3 ) By dividing with resistors VCC VCC 9 9 R1=10kΩ AN6550 AN6550 2 5 2 VEXT 5 VEE VR=10kΩ VEE 4 ) By Zener diode (VCC–VEE > = 6V) VCC 9 R> = 10kΩ AN6550 2 5 VEE VEXT VEXT