30 F2127PA050SC L177E09 D1 19

30-F2127PA050SC-L177E09
Output Inverter Application
flow 7PACK 2
1200 V / 50 A
General conditions
3phase SPWM
V GEon = 15 V
V GEoff = -15 V
R gon = 8 Ω
R goff = 8 Ω
Figure 1
IGBT
Figure 2
Typical average static loss as a function of output
current
P loss = f(I out)
80
Ploss (W)
120
Ploss (W)
FWD
Typical average static loss as a function of output
current
P loss = f(I out)
Mi*cosfi = 1
100
Mi*cosf i= -1
70
60
80
50
60
40
30
40
20
20
10
Mi*cosfi = 1
Mi*cosfi = -1
0
0
0
10
20
30
40
50
60
70
80
0
10
20
30
40
50
60
70
At
Tj =
150
At
Tj =
°C
Mi*cosφ from -1 to 1 in steps of 0,2
150
°C
Mi*cosφ from -1 to 1 in steps of 0,2
Figure 3
IGBT
Typical average switching loss
as a function of output current
Figure 4
P loss = f(I out)
100,0
fsw = 16kHz
90,0
FWD
Typical average switching loss
as a function of output current
Ploss (W)
Ploss (W)
80
Iout (A)
Iout (A)
80,0
P loss = f(I out)
45,0
fsw = 16kHz
40,0
35,0
70,0
30,0
60,0
25,0
50,0
20,0
40,0
15,0
30,0
10,0
20,0
5,0
10,0
fsw = 2kHz
fsw = 2kHz
0,0
0,0
0
10
20
30
40
50
60
70
0
80
10
20
30
40
50
60
Iout (A)
At
Tj =
150
80
Iout (A)
At
Tj =
°C
DC link = 600
V
f sw from
2 kHz to 16 kHz in steps of factor 2
copyright Vincotech
70
150
°C
DC link = 600
V
f sw from
2 kHz to 16 kHz in steps of factor 2
1
27 Jul. 2015 / Revision 1
30-F2127PA050SC-L177E09
Output Inverter Application
flow 7PACK 2
Figure 5
Phase
Figure 6
Typical available 50Hz output current
as a function Mi*cosφ
I out = f(Mi*cos φ )
Iout (A)
Iout (A)
Phase
Typical available 50Hz output current
as a function of switching frequency I out = f(f sw)
80
Th = 60°C
70
60
1200 V / 50 A
80
Th = 60°C
70
60
Th = 100°C
50
50
40
40
30
30
Th = 100°C
20
20
10
10
0
-1,0
-0,8
-0,6
-0,4
-0,2
0,0
0,2
0,4
0,6
0,8
0
1,0
1
10
100
Mi*cos φ
At
Tj =
150
fsw (kHz)
At
Tj =
°C
DC link = 600
V
f sw =
4
kHz
T h from
60 °C to 100 °C in steps of 5 °C
150
°C
DC link = 600
V
Mi*cos φ =0,8
T h from
60 °C to 100 °C in steps of 5 °C
Figure 7
Phase
Figure 8
Typical available 50Hz output current as a function of
Mi*cos φ and switching frequency
I out = f(f sw, Mi*cos φ )
Phase
Typical available 0Hz output current as a function
of switching frequency
I outpeak = f(f sw)
Iout (Apeak)
-1,00
-0,80
Iout (A)
80
Th = 60°C
70
-0,60
60
-0,40
62,0-72,0
50
0,00
42,0-52,0
Mi*cosfi
-0,20
52,0-62,0
40
0,20
30
32,0-42,0
0,40
Th = 100°C
20
22,0-32,0
0,60
10
0,80
1,00
1
2
4
8
16
32
0
64
1
10
100
fsw
At
Tj =
fsw (kHz)
150
°C
At
Tj =
DC link = 600
Th =
80
V
°C
DC link = 600
V
T h from
60 °C to 100 °C in steps of 5 °C
Mi =
copyright Vincotech
2
150
°C
0
27 Jul. 2015 / Revision 1
30-F2127PA050SC-L177E09
Output Inverter Application
flow 7PACK 2
Figure 9
Inverter
Figure 10
Inverter
Typical efficiency as a function of output power
efficiency=f(Pout)
efficiency (%)
Typical available peak output power as a function of
heatsink temperature
P out=f(T h)
Pout (kW)
1200 V / 50 A
35,0
2kHz
30,0
100,0
99,0
2kHz
98,0
25,0
97,0
16kHz
20,0
96,0
16kHz
95,0
15,0
94,0
93,0
10,0
92,0
5,0
91,0
0,0
50
55
60
65
70
75
80
85
90
95
90,0
100
0,0
5,0
10,0
15,0
20,0
25,0
30,0
Th (oC)
At
Tj =
150
DC link =
Mi =
cos φ=
f sw from
600
V
1
0,80
2 kHz to 16 kHz in steps of factor 2
40,0
45,0
Pout (kW)
°C
Figure 11
35,0
At
Tj =
150
DC link =
Mi =
cos φ=
f sw from
600
V
1
0,80
2 kHz to 16 kHz in steps of factor 2
°C
Inverter
Overload (%)
Typical available overload factor as a function of
motor power and switching frequency P peak / P nom=f(P nom,fsw)
400
350
300
250
200
150
Switching frequency (kHz)
100
Motor nominal power (HP/kW)
10,00 / 7,36
15,00 / 11,03
20,00 / 14,71
25,00 / 18,39
30,00 / 22,07
40,00 / 29,42
1
374
250
187
150
125
0
2
374
250
187
150
125
0
4
374
250
187
150
125
0
8
374
250
187
150
125
0
16
317
211
158
127
0
0
At
Tj =
150
DC link =
Mi =
cos φ=
f sw from
Th =
600
V
1
0,8
1 kHz to 16kHz in steps of factor 2
80
°C
°C
Motor eff =0,85
copyright Vincotech
3
27 Jul. 2015 / Revision 1
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