10-F0127PA008SC-L156E09 10-FZ127PA008SC-L156E08 datasheet 1200 V / 8 A Output Inverter Application flow 7PACK 0 General conditions 3phase SPWM V GEon = 15 V V GEoff = -15 V R gon = 32 Ω R goff = 32 Ω Figure 1 IGBT Figure 2 Typical average static loss as a function of output current P loss = f(I out) FWD Typical average static loss as a function of output current P loss = f(I out) Ploss (W) 14 Ploss (W) 25 Mi*cosfi = 1 12 Mi*cosf i= -1 20 10 15 8 6 10 4 5 2 Mi*cosfi = 1 Mi*cosfi = -1 0 0 0 2 4 6 8 10 12 14 0 16 2 4 6 8 10 12 Iout (A) At Tj = 149 16 Iout (A) At Tj = °C Mi*cosφ from -1 to 1 in steps of 0,2 149 °C Mi*cosφ from -1 to 1 in steps of 0,2 Figure 3 IGBT Typical average switching loss as a function of output current Figure 4 FWD Typical average switching loss as a function of output current P loss = f(I out) 20,0 Ploss (W) Ploss (W) 14 fsw = 16kHz 18,0 16,0 P loss = f(I out) 9,0 fsw = 16kHz 8,0 7,0 14,0 6,0 12,0 5,0 10,0 4,0 8,0 3,0 6,0 2,0 4,0 1,0 2,0 fsw = 2kHz fsw = 2kHz 0,0 0,0 0 At Tj = 2 149 4 6 8 10 12 0 14 16 Iout (A) At Tj = °C DC link = 600 V f sw from 2 kHz to 16 kHz in steps of factor 2 copyright Vincotech 2 149 4 6 8 10 12 14 16 Iout (A) °C DC link = 600 V f sw from 2 kHz to 16 kHz in steps of factor 2 1 24 Jul. 2015 / Revision 1 10-F0127PA008SC-L156E09 10-FZ127PA008SC-L156E08 datasheet 1200 V / 8 A Output Inverter Application flow 7PACK 0 Figure 5 Phase Figure 6 Typical available 50Hz output current as a function Mi*cosφ I out = f(Mi*cos φ ) Iout (A) 12 Iout (A) Th = 60°C Th = 100°C 10 Phase Typical available 50Hz output current as a function of switching frequency I out = f(f sw) 14 Th = 60°C 12 10 Th = 100°C 8 8 6 6 4 4 2 2 0 -1,0 -0,8 -0,6 -0,4 -0,2 0,0 0,2 0,4 0,6 0,8 0 1,0 1 10 100 Mi*cos φ At Tj = 149 fsw (kHz) At Tj = °C DC link = 600 V f sw = 4 kHz T h from 60 °C to 100 °C in steps of 5 °C 149 °C DC link = 600 V Mi*cos φ =0,8 T h from 60 °C to 100 °C in steps of 5 °C Figure 7 Phase Figure 8 Typical available 50Hz output current as a function of Mi*cos φ and switching frequency I out = f(f sw, Mi*cos φ ) Phase Typical available 0Hz output current as a function of switching frequency I outpeak = f(f sw) Iout (Apeak) -1,00 -0,80 Iout (A) 14 Th = 60°C 12 -0,60 10 -0,40 11,0-12,0 -0,20 8 0,00 9,0-10,0 0,20 Mi*cosfi 10,0-11,0 6 Th = 100°C 8,0-9,0 0,40 7,0-8,0 4 0,60 2 0,80 fsw 1 2 4 8 16 1,00 32 0 64 1 10 100 fsw (kHz) At Tj = 149 °C At Tj = DC link = 600 Th = 80 V °C DC link = 600 V T h from 60 °C to 100 °C in steps of 5 °C Mi = copyright Vincotech 2 149 °C 0 24 Jul. 2015 / Revision 1 10-F0127PA008SC-L156E09 10-FZ127PA008SC-L156E08 datasheet 1200 V / 8 A Output Inverter Application flow 7Pack 0 Figure 9 Inverter Figure 10 Inverter Typical efficiency as a function of output power efficiency=f(Pout) efficiency (%) Pout (kW) Typical available peak output power as a function of heatsink temperature P out=f(T h) 6,0 2kHz 5,0 100,0 99,0 2kHz 98,0 16kHz 97,0 4,0 96,0 3,0 16kHz 95,0 94,0 2,0 93,0 92,0 1,0 91,0 0,0 60 65 70 75 80 85 90 At Tj = 149 DC link = Mi = cos φ= f sw from 600 V 1 0,80 2 kHz to 16 kHz in steps of factor 2 90,0 95 100 Th (oC) 0,0 °C Figure 11 1,0 2,0 3,0 4,0 5,0 6,0 At Tj = 149 DC link = Mi = cos φ= f sw from 600 V 1 0,80 2 kHz to 16 kHz in steps of factor 2 7,0 8,0 9,0 Pout (kW) °C Inverter Overload (%) Typical available overload factor as a function of motor power and switching frequency P peak / P nom=f(P nom,fsw) 400 350 300 250 200 150 Switching frequency (kHz) 100 Motor nominal power (HP/kW)3,00 / 2,21 1,50 / 1,10 2,00 / 1,47 5,00 / 3,68 7,50 / 5,52 10,00 / 7,36 1 399 300 200 120 0 0 2 399 300 200 120 0 0 4 399 300 200 120 0 0 8 399 300 200 120 0 0 16 399 300 200 120 0 0 At Tj = 149 DC link = Mi = cos φ= f sw from Th = 600 V 1 0,8 1 kHz to 16kHz in steps of factor 2 80 °C °C Motor eff =0,85 copyright Vincotech 3 24 Jul. 2015 / Revision 1