Application Note 1088 Application Notes for AP3775 System Solution Prepared by Ding Xuezheng System Engineering Dept. 1. Introduction compensation and cable compensation to reduce the number of external system components. Fixed cable compensation is used in different IC versions to adapt the different voltage drop on output cable and good CV regulation is achieved. Besides, audio noise is reduced by the creative audio suppression technique. The AP3775 is an innovative Sub-5mW standby power solution from BCD semiconductor. Combined with the AP4341, the AP3775 power solution can achieve the less 5mW standby power, tight constant voltage regulation and good dynamic performance. The AP3775 is designed for driving bipolar transistor in Flyback converter, which uses Pulse Frequency Modulation (PFM) method to realize Discontinuous Conduction Mode (DCM) operation for Flyback power supplies. As to BCD zero Watt standby power solution, there is a secondary controller the AP4341 (IC2) to keep the light load voltage regulation and improve dynamic performance. The AP3775 solution can apply into 5.0V output voltage Charger/Adapter system which has ultra low standby power requirement. The AP3775 can provide accurate constant voltage (CV), constant current (CC) regulation with Primary Side Regulation (PSR) structure. It uses internal line Figure 1. Typical Application Circuit of AP3775 Figure 1 is the typical application circuit of the AP3775, which is a conventional Flyback converter with a 3-winding transformer---primary winding (NP), secondary winding (NS) and auxiliary winding (NA). The auxiliary winding is used for providing VCC supply voltage for IC and sensing the output voltage feedback signal to FB pin. Nov. 2012 Figure 2 shows the typical waveforms which demonstrate the basic operating principle of AP3775 application. And the parameters are defined as following. Idri---The driving signal of primary power switch Ip---The primary side current Is ---The secondary side current IPK---Peak value of primary side current Rev. 1. 0 BCD Semiconductor Manufacturing Limited 1 Application Note 1088 IPKS---Peak value of secondary side current VSEC---The transient voltage at secondary winding VS---The stable voltage at secondary winding when rectification diode is in conducting status, which equals the sum of output voltage VOUT and the forward voltage drop of diode VAUX---The transient voltage at auxiliary winding VA---The stable voltage at auxiliary winding when rectification diode is in conducting status, which equals the sum of voltage VCC and the forward voltage drop of auxiliary diode tSW ---The period of switching frequency tONP---The conduction time when primary side switch is “ON” tONS---The conduction time when secondary side diode is “ON” tOFF---The dead time when neither primary side switch nor secondary side diode is “ON” tOFFS---The time when secondary side diode is “OFF” tSW I dri IPK IP IPKS tOFFS IS VA VAUX VS VSEC tONP tONS tOFF Figure 2. Operation Waveforms of Flyback PSR Control System LL Mode Operation at Light Load At no load and light load, the AP3775 works in Low Light mode (LL mode) and the output voltage is detected by AP4341. In order to achieve ultra low standby power, in LL mode, the static current (ICC_NL) of the AP3775 is reduced from 250µA to 100µA, current reference VCS is high to reduce switching frequency. • The conditions of exiting LL mode---VCPC ≥90mV or tOFF<tDELAY+30µs. • The conditions of entering LL mode---VCPC<60mV and tOFF≥tDELAY+30µs. In LL mode, when the AP4341 detects the output voltage is lower than its trigger voltage, the AP4341 OUT pin emits a periodical pulse current. This pulse current will generate a Nov. 2012 pulse voltage on feedback winding through the transformer coupling. When the AP3775 detects this VPULSE (>100mV is valid), primary switch immediately turns on to provide one energy pulse to supply output terminal and primary VCC. To achieve low standby power, the lower switching frequency is necessary. But if the off time is too long, the VCC voltage will reduce to very low level. To avoid VCC being lower than UVLO, a minimum switching frequency is specified by the AP4341 (tDIS). If VO can’t be lower than trigger voltage within tDIS, AP4341 OUT pin will emit the periodical pulse current and let the primary switch turn on. Rev. 1. 0 BCD Semiconductor Manufacturing Limited 2 Application Note 1088 No Load Operation Mode 1 When the transferred energy of one switching pulse can charge the output voltage VO≥VDIS, the AP4341 will enable a 1mA current to discharge the output voltage, and the power system switching period will be the discharge time of the AP4341. Because the discharge current at no load is very small, the output voltage decreases from VDIS to VTRI very slowly. As the above mentioned, if VO doesn’t decrease to VTRI within TDIS, the primary switch will turn on again. The detailed operation waveform is shown in Figure 3. Figure 3. No Load Operation Waveforms Mode 1 No Load Operation Mode 2 When the transferred energy of one switching pulse can’t charge the output voltage VO≥VDIS, then the 1mA discharge current will not be enabled. The output voltage will be discharge to be lower than the trigger voltage of the AP4341 within the discharge time. That means the off time will be smaller than the discharge time tDIS of the AP4341, as shown in Figure 4. VO VDIS VTRI VFB tSW<tDIS IDIS 0mA Figure 4. No Load Operation Waveforms Mode 2 Dynamic Response Function_Undershoot When output load changes from light load to heavy load, the output voltage will decrease. Once the AP4341 detects VO is lower than VTRI, a pulse current IPULSE will generate. And VPULSE is generated on feedback winding through the transformer coupling due to IPULSE. When the AP3775 detects VPULSE (>90mV is valid), primary switch is “ON”. VPULSE will be valid again after a delay time (tD), which is determined by the AP3775. AP3775 working Figure 5. Undershoot Response Waveform Nov. 2012 Rev. 1. 0 BCD Semiconductor Manufacturing Limited 3 Application Note 1088 Dynamic Response Function_Overshoot When output load changes from heavy load to light load, the output voltage will rise. When the AP4341 detects VO is higher than VOVP, and the off time of the AP3775 (tOFF) is longer than 2ms, a 60mA discharge current will be enabled from VCC pin of the AP4341. Thus the output voltage will fall fast. Once the voltage is lower than VOVP, the 60mA discharge current will stop. Then output voltage falls slowly. When tOFF≥80ms and VO≥VDIS, 1mA is used to discharge the output voltage. Figure 6. Overshoot Response Waveform 2. Guideline of System Design 1. Low Standby Power Design 2. Switching Frequency Design 3. Transformer and Power Devices Design 4. Feedback Resistors Design 5. Line Compensation Design 6. Cable Compensation Design The AP4341 (IC2) is used to detect the output voltage and decide the no load operating frequency. Thus, the output voltage regulation will keep within ±5% at the whole of line and load condition. The power loss of this secondary controller is, (3) PU 2 = V o × I IC 2 2.1 Low Standby Power Design In order to achieve low standby power, the AP3775 decreases the minimum operating frequency and operating current ICC_NL. The power loss of the AP3775 is, PU 1 = V CC × I CC Where VO is output voltage and is used as the supplier of the AP4341; IIC2 is operating current of the AP4341. 2.2 Switching Frequency Design (1) _ NL As we know, in DCM Flyback converter, the stored energy of primary side will be transferred to secondary side at the time when the primary switch is turned off. And assume the current transfer efficiency from primary to secondary is ηi , then Generally, the resistor startup circuit takes the considerable power loss at no load condition since of the lower startup resistance to guarantee the shorter startup time. The AP3775 solution uses the innovative zero power dissipation startup circuit. The AP3775 uses BJT Q1’s current amplifying function, which the startup current will be amplified to over ten times, so that the startup resistors R3+R4 value can be increased to high enough. The loss of startup resistors is, PSTART = (Vindc _ nor − VTH _ ST ) /( R3 + R 4) 2 Ipks = Ipk ⋅ N PS ⋅ ηi Here, NPS is the turn ratio of primary winding to secondary winding. It is obvious that the output current IO is the average current of secondary side IS, (2) Where VTH_ST is the Startup Threshold of VCC, Vindc_nor is the rectified DC voltage from the nominal AC input voltage. Nov. 2012 (4) Io = Rev. 1. 0 t 1 Ipks ⋅ ONS 2 t SW (5) BCD Semiconductor Manufacturing Limited 4 Application Note 1088 Then, Io = PO = VO ⋅ I O = t 1 Ipk ⋅ N PS ⋅ η i ⋅ ONS 2 t SW (6) t ONS t SW (9) Where, fSW is the switching frequency. So, f SW 2 ⋅ VO = 2 IO LP ⋅ I pk ⋅ηT Always voltage of CPC pin (VCPC) is determined by, Vcpc = VDD ⋅ 1 2 ⋅ LP ⋅ I pk ⋅ f SW ⋅ ηT 2 (10) (7) When voltage at the sense resistor reaches the reference voltage set by the AP3775, the switch will be turned off and primary current reaches its maximum value, Here VDD is a constant voltage generated by IC. Then, 2 ⋅ VDD Vcpc = IO N PS ⋅ η i ⋅ I PK (8) I PK = Vcs _ ref (11) Rcs If ηT is efficiency of power transmission from transformer primary to the output, then When the constant reference VCS_REF is used, the peak current IPK is constant. From formula (8) and (10), it is obvious that VCPC and fSW increase linearly with the output current IO. VH=0.45V VCS_REF 1.55V VCPC fSW fSW 55kHz 20kHz IO 42%IO Figure 7. Relationship between VCPC, fSW and IO at Constant Peak Current Mode IO>=42%*IO_MAX and is decreased to 0.45V/1.5 when IO<42%* IO_MAX, as follows in Figure 8. In the AP3775, in order to realize audio noise suppression, two-segmented of current reference voltage VCS_REF is used except LL mode. The reference is about 0.45V when Nov. 2012 Rev. 1. 0 BCD Semiconductor Manufacturing Limited 5 Application Note 1088 AP3775 Figure 8. Relationship between VCPC, fSW and IO at Variable Peak Current Mode Then from formula (8) and (10), we can see the VCPC and fSW both has a leap at about 42% of maximum load. At the leap point, if the peak current is decreased by 1.5 times, the voltage of CPC pin at low IPK will be increased to 1.5 times, and the switching frequency fSW at low IPK will be increased to 1.52 times. So the load range in audio is largely narrowed. VCS_REF VH=0.45V VL=0.45V/1.5 36%IO 42%IO IO Figure 9. Hysteresis at Conversion between Low IPK and High IPK In order to avoid unstable operation, a hysteresis is added at the conversion between low IPK and high IPK. Considering the relationship between audio noise and flux density of transformer, deltaB≤2500 gauss is better for audio noise suppression. given by audio noise suppression. And the upper limit of the AP3775 can be up to 120kHz. But this is only the limit of the IC; the finally designed maximum switching frequency is determined by the tradeoff between the efficiency, mechanical dimensions and thermal performance. The low limitation of maximum switching frequency is Nov. 2012 Rev. 1. 0 BCD Semiconductor Manufacturing Limited 6 Application Note 1088 capacitance of primary switch. Then some margin is added to tons as, 2.3 Transformer and Power Devices Design In the design of AP3775, constant current control function will keep a fixed proportion between on-time tONS and off-time tOFFS of rectifier D1 (in Figure 1) by discharging or charging a capacitor embedded in the IC. The fixed proportion is, t ONS 4 = t SW 9 tONS = I pks ⋅ (19) From formula (4) and formula (14), we can get, Vs ⋅ Io = 2 ⋅ t SW = 4.5 t ONS (13) = 1 1 ⋅ I PKS = ⋅ N PS ⋅ ηi ⋅ I PK k k 1 ⋅ Lp ⋅ Ipk 2 ⋅ fsw ⋅ηi 2 2 Then, (14) t SW = 2.3.1 Calculate Turn Ratio of Transformer (NPS) The turn ratio of transformer should be designed first, which ensures the power converter operating in DCM within the whole conditions, tSW ≥ tONP + tONS 1 1 Lp ⋅ Ls ⋅ Ipks 2 ⋅ fsw = ⋅ ⋅ ( Ipk ⋅ N PS ⋅ηi ) 2 ⋅ fsw 2 2 N PS 2 (20) Then the output constant-current value IO is, IO = (18) VS = VO + Vd (12) It is assumed, k= LS ⋅ 1. 1 VS 2 L p ⋅ I pk ⋅ ηi 2 (21) 2 ⋅ VS ⋅ I O tONP, tONS and tSW in (15) are replaced with (16), (18) and (21), then 2 Lp ⋅ I pk ⋅ ηi (15) 2 ⋅ VS ⋅ I O 2 ≥ I pks ⋅ Lp Ls ⋅ 1.1 + I pk ⋅ Vs Vindc_min (22) As we know, if equation (13) is met at minimum input voltage and full load, it can ensure that the power converter operates in DCM in all conditions. Relationship between inductance of primary side and secondary side is, For the primary side current, Ls = t ONP = I pk ⋅ Lp Vindc When Vindc is the minimum value, the maximum tONP can be obtained. So, Vindc _ min Vindc _ min ⋅η i ⎛ k ⎞ ⋅ ⎜ − 1.1⎟ VS ⎝2 ⎠ (24) Then designed turns ratio NPS should be no more than NPS_MAX defined in formula (24). (17) 2.3.2 Check stress voltage of primary side switch and reverse voltage of secondary diode For the secondary side current, LS is the inductance of secondary winding, Vd is the forward voltage of secondary diode. If NPS is fixed by customer according in design step 2.3.1, real stress voltage of primary side switch and reverse voltage of secondary diode can be calculated. There is an oscillating signal on FB waveform after secondary Schottky diode current decrease to zero, which is caused by primary inductance and equivalent output Nov. 2012 (23) 2 N PS ≤ N PS _ MAX = Vindc is the rectified DC voltage of input. Lp N PS At full load, the system will work in the boundary of CC regulation. IO can be given by formula (14),the following can be obtained, (16) Where LP is the inductance of primary winding. t ONP_MAX = I pk ⋅ Lp Rev. 1. 0 BCD Semiconductor Manufacturing Limited 7 Application Note 1088 The maximum stress voltage of primary side switch is, Vds _ switch = Vdc_spike + Vindc_max V ⋅ NP + S NS PS = VS ⋅ I O = Where, fSW was set by the user based on definite requirement. Then, LP can be gotten by, LP = Maximum reverse voltage of secondary side, Vindc_max ⋅ N S NP Np = NS = (31) NP N PS (32) Turns of auxiliary winding is, (27) NA = N S ⋅ VA VS (33) 2.3.6 Check the maximum duty cycle of primary side Vcs _ ref I pk LP ⋅ I PK LP ⋅ I PK ≥ Ae ⋅ ∆B Ae ⋅ B max As NPS and NP are fixed, we can get NS by, In the AP3775, 0.45V is an internal reference voltage. If the sensed voltage VCS_REF reaches 0.45V, the power switch will shut down and tONP will be ended. RCS = (30) The turns of primary winding, 2.3.3 Calculate the peak current of primary side and current sensed resistor (IPK & RCS) IPK can be calculated by the output current. k ⋅ IO N PS ⋅ ηi 2 ⋅ PS 1 ⋅ 2 I ⋅ f SW ηi 2 PK 2.3.5 Calculate the turns of primary, secondary and auxiliary (NP, NS, NA) (26) For Flyback converter design, higher turns ratio NPS brings higher stress voltage of primary side switch, higher transforming efficiency, and the lower reverse voltage of secondary diode. Finally, in design of turns ratio NPS and NPA, formula (24), (25), (26), should be totally considered. I pk = (29) (25) Be careful that the value of Vdc_spike is determined by the snubber circuit design. Vdr = VS + 1 2 2 ⋅ L p ⋅ I pk ⋅ f SW ⋅ ηi 2 After turn ratio of primary side and secondary side is designed, the maximum duty cycle of primary side at low line voltage can be calculated again. (28) So RCS can be obtained and selected with a real value from the standard resistor series. We recommended using 1% tolerance resistors for RCS. After RCS is selected, IPK should be modified based on the selected RCS. Considering the Volt-second balance between magnetizing and de-magnetizing, the formula of duty cycle is, D max = (VO + Vd ) ⋅ N t ons ⋅ Vindc ⋅ ηi t sw (34) 2.3.4 Calculate the inductance of primary side---LP The primary side inductance LP is relative with the stored energy. LP should be big enough to store enough energy, so that PO_MAX can be obtained from this system. 2.3.7 Check reverse voltage of auxiliary diode If NP and NA are fixed according in design step 2.3.5, real reverse voltage of auxiliary diode can be calculated by formulas (26). According to formula (20), the output power can be given by, Nov. 2012 Rev. 1. 0 BCD Semiconductor Manufacturing Limited 8 Application Note 1088 2.4 Feedback Resistors Design VD VIN NP VO NS NA RFB1 Q FB VFB OUT RFB2 Figure 10. Feedback Resistors Circuit From above Figure 10, Vo = VFB ⋅ RFB2 are within 5kΩ to 100kΩ. (R FB1 + R FB 2 ) N S ⋅ − VD R FB 2 NA 2.5 Line Compensation Design (35) R FB1 Vo + VD = ⋅ NA −1 RFB 2 N S ⋅ VFB The internal line compensation function in the AP3775 is shown in Figure 11. S1 is closed when the primary switch is “ON”. The line voltage can be detected from the FB pin. The detected voltage internally compensates the peak current. So the line compensation is determined by RLINE. In different applications, the value of RLINE is different. (36) Through adjusting RFB1 and RFB2, a suitable output voltage can be achieved. The recommended values of RFB1 and VAUX VDD tONP RFB1 gm OUT S1 FB RFB2 RLINE RCS ILINE VCS Figure 11. Line Compensation Circuit Nov. 2012 Rev. 1. 0 BCD Semiconductor Manufacturing Limited 9 Application Note 1088 Figure 12. Waveform of FB Pin there is a total voltage increase of 6% at VFB when the output is at full load (IOUT_MAX). And if the output is at 10%*IOUT_MAX, the increase voltage of VFB is 0.6%. Proper version of IC can be chosen according to the resistance of the output cable. The negative voltage VN of FB pin (in Figure12) is linear to line voltage. The AP3775 samples VN to realize the line compensation. VN = Vindc ⋅ NA R FB 2 ⋅ N P R FB1 + R FB 2 (37) CABLE COMPENSATION SECTION Cable AP3775 VFB Compensation AP3775B _CABLE/VFB % Voltage The compensated voltage of line compensation (VCS_LINE) can be calculated by the following formula, VCS _ LINE = Vin _ DC ⋅ NA RFB 2 ⋅ ⋅ g m ⋅ RLINE N P RFB1 + RFB 2 (38) tdelay LP ∆VFB % = t delay Lp ⋅ Rcs ) /( ∆VOUT _ CABLE = ∆VFB % ⋅ VFB ⋅ NA RFB 2 ⋅ ⋅ gm ) N P RFB1 + RFB 2 (41) VFB Then from Figure 8, Then RLINE can be adjusted to achieve excellent line regulation of output current. RLINE = ( ∆VFB _ CABLE (39) ⋅ Rcs 3 4 5 % Assume, This is designed to compensate the additional voltage of VCS introduced by tdelay, which is the delay time of internal drivers of IC and primary side switch. Vdelta = Vindc ⋅ 5 6 7 % RFB1 + RFB 2 N S ⋅ = I O _ MAX ⋅ RCABLE RFB 2 NA (42) Then after ∆VFB% is calculated, proper version of the AP3775 can be chosen accordingly. (40) ∆VFB % = I O _ MAX ⋅ RCABLE /(VFB ⋅ 2.6 Cable Compensation Design RFB1 + R FB 2 N S ⋅ ) RFB 2 NA (43) Design Example (for 5V/1.2A application): Two versions of IC are designed to meet different requirement for cable voltage compensation. As we know, an increase voltage at VFB (∆VFB_CABLE) will introduce an increase voltage at VOUT (∆VOUT_ CABLE), which is a linear function of the output load (IOUT). Then in application of the AP3775, CPC pin detects the load information and a corresponding delta voltage is added to VFB to compensate the voltage drop at output cable. Specification: Input voltage: 85VAC to 265VAC Output voltage @ cable: VO_CABLE=5V Output current: IO=1.2A Output voltage @ PCB: VO=5.13V, (AWG26 Cable, Length of Cable=100cm, RCABLE=0.267Ω) As defined in datasheet below, for example, in the AP3775, Nov. 2012 Rev. 1. 0 BCD Semiconductor Manufacturing Limited 10 Application Note 1088 Other setting by users: Switching frequency: fSW=65kHz Forward voltage of secondary diode: Vd=0.4V Forward voltage of auxiliary diode: Vda=1.1V VCC voltage: VCC=14V Core_type: RM5 (Ae=23.7mm2), BMAX<3000GS Vdc_spike=50V (with snubber circuit) Np = LP ⋅ I PK LP ⋅ I PK ≥ = 65 T Ae ⋅ ∆B Ae ⋅ B max (51) We choose NP=90T NS = NP = 6T N (52) NA = N S ⋅VA = 16 T VS (53) Design Steps: 1) Calculate Turn Ratio of Transformer (NPS) N PS ≤ N PS _ MAX = Vindc _ min ⋅ η i ⎛ k ⎞ ⋅ ⎜ − 1.1⎟ = 15.8 VS 2 ⎠ ⎝ 6) Check the maximum duty cycle of primary side (44) The maximum duty cycle of primary side is calculated as following, (45) Vindc_min = Vinac_min ⋅ 2 − 40 D= Considering some margin for Flyback PSR control, we choose NPS=15. (VO + Vd ) ⋅ N ⋅ 0.4 = 0.43 Vindc ⋅ η i (54) 7) Check reverse voltage of auxiliary diode 2) Check stress voltage of primary side switch and reverse voltage of secondary diode. Vdar = V A + According to formulas (25), (26) and the selected NPS, proper power devices could be chosen. Vds _ switch = Vdc_spike + Vindc_max + Vdr = VS + Vindc_max ⋅ N S NP VS ⋅ N P = 505V < 700V NS = 30V < 40V Vindc_max ⋅ N A NP = 80V (55) 8) Feedback Resistors (46) RFB1 Vo + VD = ⋅ N A − 1 = 2.98 RFB 2 N S ⋅ VFB (47) RFB1=29.8kΩ, RFB2=10kΩ (56) 9) Line Compensation Resistors 3) Calculate the peak current of primary side and current sense resistor (IPK & RCS) I pk = RCS = I pks N ⋅ηi = k ⋅ IO ≈ 380mA N ⋅ηi VCS ≈ 1.2 Ω I pk RLINE = ( 2 ⋅ VS ⋅ I O = 1.5mH 2 2 I PK ⋅ f SW ⋅ η i ⋅ Rcs ) /( NA RFB 2 ⋅ ⋅ g m ) = 6.3k Ω N P RFB1 + RFB 2 (57) VFB=3.7V, the same in two versions of the AP3775. Then, (49) VFB % = I O _ MAX ⋅ RCABLE /(VFB ⋅ RFB1 + RFB 2 N S ⋅ ) = 5 .8 % RFB 2 NA (58) According to datasheet information, the AP3775 is a better choice. (50) VO _ FL = VO _ NL + (VFB % ⋅ VFB ⋅ RFB1 + RFB 2 N S ⋅ ) − I O _ MAX ⋅ RCABLE = 5.01V RFB 2 NA (59) Where VO_NL=5V. Therefore, the output voltage at cable terminal at full load is a little higher than the voltage at light load. 5) Calculate the turns of primary, secondary and auxiliary (NP, NS, NA) Nov. 2012 Lp 10) Cable Compensation Choice (48) 4) Calculate the inductance of primary side---LP LP = t delay Rev. 1. 0 BCD Semiconductor Manufacturing Limited 11 Application Note 1088 Design Results Summary 1.Maximum peak current of primary side and RCS IPK 380 mA Peak current of primary side RCS 1.2 Ω LP 1.5 mH NPS 15 NP 90 T Turns of primary side NS 6 T Turns of secondary side NA 16 T Turns of auxiliary side Current sensed resistor 2.Transformer DMAX Inductance of primary side Turn ratio of primary and secondary 0.43 Maximum duty cycle of primary side at VINDC=80V 3. Primary power switch and diode Vds_switch 505 V Voltage stress of primary power switch Vdr 30 V Maximum reverse voltage of secondary diode Vdar 80 V Maximum reverse voltage of auxiliary diode 4. Voltage feedback resistors RFB1 28.9k Ω Feedback resistor at upside from auxiliary side to FB pin RFB2 10k Ω Feedback resistor at downside from FB pin to GND Ω Line compensation resistor 5. Line compensation resistor RLINE 6.3k 6.Cable Compensation IC version AP3775 VO_NL 5 V Output voltage @ light load VO_FL 5.01 V Output voltage @ full load 3. Summary In order to get good performance of the AP3775, it is important to correctly design standby power, switching frequency, transformer parameters, feedback resistance and line compensation resistance. This application note only Nov. 2012 gives a preliminary design guideline about these aspects and considers ideal conditions, so some parameters need to be adjusted slightly on the basis of the calculated results. Rev. 1. 0 BCD Semiconductor Manufacturing Limited 12 Application Note 1088 4. Application of AP3775 with AP4341 FR1 L1 TR1 D1 C8 R 12 R3 D 4 to D7 R6 C1 + C2 R7 D2 + R4 OUT VCC GND R11 L2 C5 D3 C3 IC2 AP4341 + + C4 VO R10 Q1 IC1 AP3775 VCS VCC CPC R5 R16 OUT FB C6 EM GND IS R17 R2 Figure 13. Typical Application Circuit of AP3775 with AP4341 In Primary Side Regulation of the AP3775 application, the AP4341 must be used at secondary side as the output voltage regulator at light load, excellent dynamic response and low standby power can be achieved. When detecting the output voltage lower than a certain level, AP4341 outputs periodical signals which will be coupled to auxiliary side and detected by the AP3775, and the AP3775 will begin an operating pulse, then the output voltage will Nov. 2012 rise. By fast response and cooperation, the AP4341 and AP3775 can maintain a constant output voltage with very low operating frequency at light load and also can effectively improve the transient performance for Primary Side Regulation power system. Beside, dummy load is not needed at secondary side and as a result standby power will be decreased. Rev. 1. 0 BCD Semiconductor Manufacturing Limited 13