80 M006PNB010SAx K615x D2 19

80-M006PNB010SA*-K615*
datasheet
®
Output Inverter Application
MiniSKiiP 0 PIM
600 V / 10 A
General conditions
3phase SPWM
V GEon = 15 V
V GEoff = -15 V
R gon = 32 Ω
R goff = 32 Ω
Figure 1
IGBT
Figure 2
Typical average static loss as a function of output current
P loss = f(I out)
Ploss (W)
18
Ploss (W)
FWD
Typical average static loss as a function of output current
P loss = f(I out)
Mi*cosfi = 1
16
12
Mi*cosf i= -1
10
14
8
12
10
6
8
4
6
4
2
2
Mi*cosfi = 1
Mi*cosfi = -1
0
0
0
2
4
150
Tj=
6
8
10
12
0
14
16
Iout (A)
4
6
8
10
12
14
16
Iout (A)
°C
150
Tj=
Mi*cosφ from -1 to 1 in steps of 0,2
°C
Mi*cosφ from -1 to 1 in steps of 0,2
Figure 3
IGBT
Typical average switching loss
as a function of output current
Figure 4
FWD
Typical average switching loss
as a function of output current
P loss = f(I out)
Ploss (W)
Ploss (W)
2
9
fsw = 16kHz
8
P loss = f(I out)
4
3,5
fsw = 16kHz
7
3
6
2,5
5
2
4
1,5
3
1
2
0,5
1
fsw = 2kHz
fsw = 2kHz
0
0
0
2
4
6
8
10
12
14
16
0
2
4
6
8
10
Iout (A)
Tj=
150
14
16
Iout (A)
°C
Tj=
DC link = 320
V
f sw from 2 kHz to 16 kHz in steps of factor 2
copyright Vincotech
12
150
°C
DC link = 320
V
f sw from 2 kHz to 16 kHz in steps of factor 2
1
12 Jan. 2016 / Revision 3
80-M006PNB010SA*-K615*
datasheet
®
Output Inverter Application
MiniSKiiP 0 PIM
Figure 5
Phase
Figure 6
Typical available 50Hz output current
as a function Mi*cosφ
I out = f(M i*cos φ)
Phase
Typical available 50Hz output current
as a function of switching frequency I out = f(f sw)
Iout (A)
16
Iout (A)
600 V / 10 A
Ts = 60°C
14
16
Ts = 60°C
14
Ts = 100°C
12
12
10
10
8
8
6
6
4
4
2
2
0
Ts = 100°C
0
-1
-0,8
-0,6
-0,4
150
Tj=
-0,2
0
0,2
0,4
0,6
0,8
1
Mi*cos φ
1
°C
150
Tj=
DC link = 320
V
f sw =
4
kHz
T S from
60 °C to 100 °C in steps of 5 °C
10
100
fsw (kHz)
°C
DC link = 320
V
M i*cos φ = 0,8
T S from
60 °C to 100 °C in steps of 5 °C
Figure 7
Phase
Figure 8
Typical available 50Hz output current as a function of
Mi*cos φ and switching frequency
I out = f(f sw, M i*cos φ)
Iout (Apeak)
-1
-0,8
Iout (A)
Phase
Typical available 0Hz output current as a function
of switching frequency
I outpeak = f(f sw)
16
14
Ts = 60°C
-0,6
12
-0,4
13,0-14,0
10
12,0-13,0
0
11,0-12,0
Mi*cosfi
-0,2
8
Ts = 100°C
0,2
10,0-11,0
0,4
9,0-10,0
0,6
6
4
2
0,8
8,0-9,0
0
1
1
2
4
8
16
32
64
1
fsw
(kHz)
10
150
°C
Tj=
DC link = 320
TS=
80
V
°C
DC link = 320
V
T S from
60 °C to 100 °C in steps of 5 °C
Tj=
Mi=
copyright Vincotech
2
150
fsw (kHz)
100
°C
0
12 Jan. 2016 / Revision 3
80-M006PNB010SA*-K615*
datasheet
®
Output Inverter Application
MiniSKiiP 0 PIM
Figure 9
Inverter
Figure 10
Inverter
Typical efficiency as a function of output power
efficiency=f(P out)
efficiency (%)
Typical available peak output power as a function of
heatsink temperature
P out=f(T S)
Pout (kW)
600 V / 10 A
4
2kHz
3,5
16kHz
100
99,5
99
3
98,5
2,5
98
2
97,5
2kHz
97
1,5
96,5
1
96
16kHz
0,5
95,5
95
0
60
65
70
75
80
85
90
95
o
0
100
0,5
1
1,5
2
2,5
3
Ts ( C)
150
Tj=
DC link = 320
Mi=
1
°C
Tj =
V
DC link = 320
Mi =
1
0,80
2 kHz to 16 kHz in steps of factor 2
cos φ=
f sw from
cos φ=
f sw from
Figure 11
150
3,5
4
4,5
Pout (kW)
°C
V
0,80
2 kHz to 16 kHz in steps of factor 2
Inverter
Overload (%)
Typical available overload factor as a function of
motor power and switching frequency P peak / P nom=f(P nom,f sw)
500
450
400
350
300
250
200
Switching frequency (kHz)
150
Motor nominal power (HP/kW)
100
1,00 / 0,74
1,50 / 1,10
2,00 / 1,47
3,00 / 2,21
5,00 / 3,68
7,50 / 5,52
1
399
266
200
133
0
0
2
399
266
200
133
0
0
4
399
266
200
133
0
0
8
399
266
200
133
0
0
16
399
266
200
133
0
0
Tj=
150
DC link = 320
Mi=
1
cos φ=
f sw from
TS=
°C
V
0,8
1 kHz to 16kHz in steps of factor 2
80
°C
Motor eff =0,85
copyright Vincotech
3
12 Jan. 2016 / Revision 3