80 M006PNB010SAx K614x D2 19

80-M006PNB006SA*-K614*
datasheet
Output Inverter Application
MiniSKiiP® PIM 0
600 V / 6 A
General conditions
3phase SPWM
V GEon = 15 V
V GEoff = -15 V
R gon = 64 Ω
R goff = 64 Ω
Figure 1
IGBT
Figure 2
Typical average static loss as a function of output current
P loss = f(I out)
FWD
Typical average static loss as a function of output current
P loss = f(I out)
Ploss (W)
16
Ploss (W)
25
Mi*cosfi = 1
14
20
Mi*cosf i= -1
12
10
15
8
10
6
4
5
2
Mi*cosfi = -1
Mi*cosfi = 1
0
0
0
2
4
150
Tj=
6
8
10
12
14
Iout (A)
0
16
°C
IGBT
Typical average switching loss
as a function of output current
8
10
12
14
Iout (A)
16
°C
Figure 4
FWD
Typical average switching loss
as a function of output current
P loss = f(I out)
Ploss (W)
Ploss (W)
6
Mi*cosφ from -1 to 1 in steps of 0,2
Figure 3
8
7
4
150
Tj=
Mi*cosφ from -1 to 1 in steps of 0,2
2
fsw = 16kHz
P loss = f(I out)
3,0
2,5
6
fsw = 16kHz
2,0
5
1,5
4
3
1,0
2
0,5
1
fsw = 2kHz
fsw = 2kHz
0,0
0
0
Tj=
2
150
4
6
8
10
12
14Iout (A)
0
16
°C
Tj=
DC link = 320
V
f sw from
2 kHz to 16 kHz in steps of factor 2
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2
150
4
6
8
10
12
14
16
Iout (A)
°C
DC link = 320
V
f sw from
2 kHz to 16 kHz in steps of factor 2
1
13 Jan. 2016 / Revision 3
80-M006PNB006SA*-K614*
datasheet
Output Inverter Application
MiniSKiiP® PIM 0
Figure 5
Phase
Figure 6
Iout (A)
Th = 60°C
Th = 100°C
8
9
Th = 60°C
8
7
7
6
6
5
5
4
4
3
3
2
2
1
1
0
-1,0
Phase
Typical available 50Hz output current
as a function of switching frequency I out = f(fsw)
Iout (A)
Typical available 50Hz output current
as a function Mi*cosφ
I out = f(Mi*cos φ)
9
600 V / 6 A
Th = 100°C
0
-0,8
Tj=
-0,6
-0,4
150
-0,2
0,0
0,2
0,4
0,6
0,8
1,0
Mi*cos φ
1
°C
150
Tj=
DC link = 320
V
f sw =
4
kHz
T S from
60 °C to 100 °C in steps of 5 °C
10
fsw (kHz)
100
°C
DC link = 320
V
M i*cos φ = 0,8
T S from
60 °C to 100 °C in steps of 5 °C
Figure 7
Phase
Figure 8
Typical available 50Hz output current as a function of
Mi*cos φ and switching frequency
I out = f(fsw, Mi*cos φ)
Iout (Apeak)
-1,00
-0,80
Iout (A)
-0,60
9
Th = 60°C
8
7
-0,40
11,0-12,0
Phase
Typical available 0Hz output current as a function
of switching frequency
I outpeak = f(fsw)
6
Th = 100°C
-0,20
9,0-10,0
0,00
8,0-9,0
7,0-8,0
5
Mi*cosfi
10,0-11,0
4
0,20
6,0-7,0
3
0,40
2
0,60
1
2
4
8
16
32
0,80
1
1,00
0
64
1
fsw
(kHz)
10
150
°C
Tj=
DC link = 320
TS=
80
V
°C
DC link = 320
V
T S from
60 °C to 100 °C in steps of 5 °C
Tj=
Mi=
copyright Vincotech
2
150
fsw (kHz)
100
°C
0
13 Jan. 2016 / Revision 3
80-M006PNB006SA*-K614*
datasheet
Output Inverter Application
MiniSKiiP® PIM 0
Figure 9
Inverter
Figure 10
Inverter
Typical efficiency as a function of output power
efficiency=f(P out)
efficiency (%)
Typical available peak output power as a function of
heatsink temperature
P out=f(T S)
Pout (kW)
600 V / 6 A
2,5
2kHz
100,0
2,0
2kHz
99,0
98,0
16kHz
97,0
1,5
96,0
16kHz
95,0
1,0
94,0
93,0
0,5
92,0
91,0
0,0
90,0
60
65
150
Tj=
DC link = 320
Mi=
1
cos φ=
f sw from
70
75
80
85
90
95
100
Ts ( o C)
0,0
0,5
°C
Tj=
V
DC link = 320
Mi=
1
0,80
2 kHz to 16 kHz in steps of factor 2
cos φ=
f sw from
Figure 11
150
1,0
1,5
2,0
2,5
3,0
3,5
4,0
4,5
Pout (kW)
°C
V
0,80
2 kHz to 16 kHz in steps of factor 2
Inverter
Overload (%)
Typical available overload factor as a function of
motor power and switching frequency P peak / P nom=f(P nom,f sw)
400
350
300
250
200
150
Switching frequency (kHz)
Motor nominal power (HP/kW)
100
0,50 / 0,37
0,75 / 0,55
1,00 / 0,74
1,50 / 1,10
2,00 / 1,47
3,00 / 2,21
1
479
320
240
160
120
0
2
479
320
240
160
120
0
4
479
320
240
160
120
0
8
479
320
240
160
120
0
16
479
320
240
160
120
0
Tj=
150
DC link = 320
Mi=
1
cos φ=
f sw from
Th=
°C
V
0,8
1 kHz to 16kHz in steps of factor 2
80
°C
Motor eff =0,85
copyright Vincotech
3
13 Jan. 2016 / Revision 3