Mass flow versus volumetric flow

Mass flow versus volumetric flow
Introduction
This application note describes the difference
between mass flow in terms of volumetric flow at
standard conditions (1013.25 hPa, 0 °C) and
volumetric flow at nonstandard conditions.
Mass flow is a dynamic mass per time unit measured
in grams per minute (g/min). By referencing a
volumetric flow (cm3/min) to its known temperature
and pressure, an exact mass flow can be calculated.
It is common in the industry to specify mass flow in
terms of volumetric flow at standard (reference)
conditions.
Note:
Attention must be paid regarding the stated reference
conditions when flow sensors are specified in
standard volumetric flow such as sccm or slpm.
Standard temperature and pressure (STP) is usually
defined as being at 0°C (273.15 K) and 1013.25 hPa
(1 atm). However, standard temperature may also be
specified as 20 °C or 25 °C. Sometimes these
reference conditions may also be referred to as
normal temperature and pressure (NTP). Special
industrial branches may even have their own
definitions, e.g. the gas industry may reference flow
volume to a temperature of 70 °F.
In accordance with these standards, First Sensors
mass flow sensors are specified as having volumetric
flow at calibration reference conditions of 1013.25 hPa
and 0 °C. These conditions are referred to as
standard conditions and calibration units for these
sensors are sccm (standard cubic centimeters per
minute) or slpm (standard liters per minute).
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Mass flow versus volumetric flow
1. Calculating true mass flow from volumetric flow
A volumetric flow at standard conditions translates to
a specific mass flow rate.
For example, 200 cm3/min of dry air at standard
conditions of temperature and pressure (200 sccm)
calculates to a mass flow of 0.258 g/min as will be
shown below.
Gas density is defined as:
ρ=
Definitions:
•
The ideal gas law,
PV = nRT
can be solved for the gas volume to get:
(4)
With equation (3) mass flow can be redefined as:
•
m
=
mP •
⋅V
nRT
(5)
•
For a volumetric flow rate of VS = 200 cm3/min at
standard conditions of 273.15 K and 1 atm the true
mass flow then calculates to
•
m
= 0.258 g min
•
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(3)
•
m
= ρ⋅V
Number of molecules of gas [mole]
Universal gas constant [(cm3•atm)/(mole•K)]
Absolute temperature [K]
Gas density [g/cm3]
Mass [g]
Mass flow [g/min]
Volumetric flow [cm3/min]
Volumetric flow at standard conditions [cm3/min]
nRT
P
mP
nRT
Mass flow is equal to density times volumetric flow rate:
P = Pressure [hPa][atm]
V = Volume [cm3]
V=
(2)
Substituting equation (1) into equation (2) redefines
gas density as:
ρ=
n =
R =
T =
ρ =
m =
•
m
=
•
V =
•
VS =
m
V
VS
m
n
P
R
T
=
=
=
=
=
=
200 cm3/min
28.949 grams in 1 mole air
1 Mol
1 atm (1013.25 hPa)
82.1 (cm3•atm)/(mole•K)
273.15 K (0 °C)
(1)
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Mass flow versus volumetric flow
2. Calculating volumetric flow from true mass flow
First Sensors flow sensors are mass flow devices
rather than volumetric ones. At a constant mass flow,
these sensors will give a constant output voltage even
if the measured air or gas volume changes due to
pressure or temperature changes.
Confusion may result when mass flow sensors are
used with volumetric devices, such as rotameters.
Accurate volumetric flow calculations for mass flow
devices require consideration of both temperature and
pressure ranges.
In contrast to mass flow sensors, volumetric devices
indicate different flow rates at varying temperatures
and pressures. Simple calculations can be used to
show the relationship between mass flow and
nonstandard volumetric flow.
For example, a 200 sccm flow sensor of the WBA
series with a mass flow rate of 0.258 g/min (200
sccm) at standard pressure of 1013.25 hPa but
nonstandard temperature of 25 °C has a 5 V output
voltage, indicating a standard flow rate of 200 sccm.
The rotameter, however, would indicate a nonstandard
volumetric flow rate.
By rearranging equation (5) the corresponding
volumetric flow at nonstandard conditions of 25 °C
can be calculated for the mass flow measured by the
WBA sensor.
•
V=
nRT •
⋅m
mP
(6)
•
V = 218.3 cm3 min
•
m
m
n
P
R
T
=
=
=
=
=
=
0.258 g/min
28.949 grams in 1 mole air
1 mole
1 atm (1013.25 hPa)
82.1 (cm3•atm)/(mole•K)
298.15 K (25 °C)
In this example the mass flow rate of 0.258 g/min at
standard conditions, which corresponds to a
volumetric flow of 200 sccm, translates to a
nonstandard volumetric flow of 218.26 cm3/min for an
increased gas temperature of 25 °C.
This increase reflects the fact that as temperature
rises, gas expands, placing more distance between
gas molecules (see Fig. 1). More distance between
molecules means less mass in a given volume. If
mass flow is kept constant, and temperature
increases, volume flow increases to pass the same
amount of mass (molecules) across the sensor.
Fig. 1: Increased volumetric flow due to temperature increase T2 > T1 , constant mass flow and pressure.
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Mass flow versus volumetric flow
3. Calculating nonstandard from standard volumetric flow
•
The actual, nonstandard volumetric flow VX can be found
•
with standard volumetric flow VS (PS= 1013,25 hPa,
TS= 0 °C) when the actual temperature and pressure of
the measured gas (TX, PX) is known.
If mass flow is held constant over temperature and
pressure, then the following is true:
•
This method eliminates the use of gas density values
at reference and actual conditions.
Therefore,
mPS •
mPX •
⋅ VX =
⋅ VS
nRTX
nRTS
Further definitions:
•
VS
= Volumetric flow at standard conditions
•
VX
TS
TX
PS
PX
•
mS
•
mX
=
=
=
=
=
=
=
Volumetric flow at nonstandard conditions
Temperature at standard conditions
Temperature at nonstandard conditions
Pressure at standard conditions
Pressure at nonstandard conditions
Mass flow at standard conditions
Mass flow at nonstandard conditions
•
Solving for VX yields:
•
•
VX = VS ⋅
PS TX
⋅
PX TS
(7)
The actual, nonstandard volumetric flow at 25 °C is found
to be
•
VX = 218.3 cm3 / min
•
VS
PS
PX
TS
TX
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•
mS = m X
=
=
=
=
=
200 cm3/min
1 atm (1013.25 hPa)
1 atm (1013.25 hPa)
273.15 K (0 °C)
298.15 K (25 °C)
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