ONSEMI AND8109

Theory of Operation
Prepared by: Mark Scholten
Senior Applications Engineer
http://onsemi.com
The LM317L wants to see 1.25 V between its VOUT pin
and the Vadj pin, and it will do whatever it can to keep that
voltage differential between them. So if a resistor is put in
series with the output, and the Vadj pin is connected to the
load side of the sense resistor, a current source is set up
which follows Equation 1:
1.25
IOUT +
(Approximately)
Rsense
But what if a series/parallel combination of LEDs is
wanted? The following circuit works fine, assuming that
there are not large variations in the forward voltage drop of
the LEDs. There could be a problem however if one of the
strings opens up for some reason. The LEDs that remain
would have 50% more current flowing through them, which
could cause them to be driven too hard and fail. So how does
one get around this problem?
(eq. 1)
VIN
LM317L
VOUT
IOUT
Rsense
VIN
LM317L
VOUT
IOUT
Rsense
Vadj
Rload
Vadj
LED1
LED4
LED7
LED2
LED5
LED8
LED3
LED6
LED9
Figure 1.
Figure 3.
In order to set up a constant current source for an LED
string, the same circuit can be used by simply substituting
Rload with an LED string, as shown below.
VIN
LM317L
VOUT
The following circuit takes care of this issue by splitting
up the current sense resistor into three resistors, one for each
leg of the LED string. The current through any one of the
LED strings is set by Equation 2:
IOUT
Rsense
IOUT +
LED1
Vadj
1.25 V ) Vsat
(Approximately)
R1
(eq. 2)
LED2
LED3
Figure 2.
 Semiconductor Components Industries, LLC, 2003
January, 2003 – Rev. 0
1
Publication Order Number:
AND8109/D
AND8109/D
VIN
VOUT
LM317L
Vadj
R4
Rsense1
Q1
R5
Rsense2
MPS2222
Q2
R6
MPS2222
Q3
MPS2222
Rsense3
LED1
LED4
LED7
LED2
LED5
LED8
LED3
LED6
LED9
Figure 4.
the sense resistor for that leg won’t have any voltage across
it, turning ‘off’ the transistor and disconnecting its sense
resistor from the Vadj pin. Therefore, the other two LED
strings are unaffected by the fault. This same scheme can be
expanded to accommodate as many LED strings as needed.
When the circuit operates properly and all the LEDs are
running, the three sense resistors have about 1.25 V across
them, which turns the transistor switches ‘on’. This connects
all three sense resistors back to the Vadj pin allowing the
proper current to go through each leg. If one string opens up,
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AND8109/D